[英]Parse an xml file with python
Hese is the file the file.xml file xml file link Hese是该文件file.xml文件xml文件链接
<?xml version="1.0" encoding="UTF-8"?>
<users>
<user data-id="101">
<nom>Zorro</nom>
<metier>Danseur</metier>
</user>
<user data-id="102">
<nom>Hulk</nom>
<metier>Footballeur</metier>
</user>
<user data-id="103">
<nom>Zidane</nom>
<metier>Star</metier>
</user>
<user data-id="104">
<nom>Beans</nom>
<metier>Epicier</metier>
</user>
<user data-id="105">
<nom>Batman</nom>
<metier>Veterinaire</metier>
</user>
<user data-id="106">
<nom>Spiderman</nom>
<metier>Veterinaire</metier>
</user>
</users>
for example: I want to show the metier for each user 例如:我想显示每个用户的等级
from lxml import etree
tree = etree.parse("file.xml")
for metier in tree.xpath("/users/user/metier"):
print(metier.text)
The script is run without problem but it shows nothing. 该脚本可以正常运行,但是什么也没显示。 It seems like
tree.xpath("/users/user/metier")
is empty!! 好像
tree.xpath("/users/user/metier")
是空的!
tree.xpath
searches relative to the root-element <users>
. tree.xpath
相对于根元素<users>
。 So users
must not be part of the path: 因此,
users
一定不能成为路径的一部分:
from lxml import etree
tree = etree.parse("file.xml")
for metier in tree.xpath("user/metier"):
print(metier.text)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.