PHP-访问作为数组元素的对象的属性的最佳方法是什么

Question

I have an object which is an array of JSON objects. Kinda Like this,

$object = [
 {
   "id":1,
   "name":"blue",
   "order":4
  },
 {
   "id":2,
   "name":"green",
   "order":6
  },
 {
   "id":3,
   "name":"yellow",
   "order":2
  }
]

I wanted to access the properties in a simple way and a single line maybe like this,

Say if I wanted the "order" of the object with name "blue"

$blue_order = $object[something]->[name="blue"]->order;

Kinda mixed Jquery in this. But I hope you understand. Right now the best I've got is this,

for($i=0; $i<count($object); $i++){
 if($object[$i]->name == "blue"){
  $blue_order = $object[$i]->order;
 }
}

This seems very inefficient though and I don't want to use a loop because the array is very large and looping through it will be very slow. So how do I do this?

I used a "for" loop instead of foreach because the array can be null. And also the order of the array elements will not always be the same.

So I can't do something like

$object[0]->order 

Answer 1

You could still use foreach but check if the array isn't empty first, like this:

if(!empty($object)){
  foreach($object as $element){
    if($element->name == "blue"){
      $blue_order = $element->order;
    }
  }
}

Also, your code looks efficient to me, what I would probably add is a break after you find the value, like this:

if(!empty($object)){
  foreach($object as $element){
    if($element->name == "blue"){
      $blue_order = $element->order;
      break;
    }
  }
}

If your object has a lot of information and you're going to do a lot of searches, then you could do some pre-processing so it get easier to search, like this:

$object_by_name = array();
if(!empty($object)){
  foreach($object as $element){
    $object_by_name[$element->name] = $element;
  }
}

Then, you could search it like this:

if(!empty($object_by_name['blue'])){
  $blue_order = $object_by_name['blue']->order
}

Answer 2

Keep it simple.

you're writing way too much code.

$array_list = ($array_list)?:[];
$array_list = array_filter($array_list,function($var) {
    return ($var->name=="blue");
});
$order = ($array_list)? $array_list[0]->order :'';

Happy coding

Answer 3

<?php

$arr = array(
 array('id'=>1,'name'=>'blue','order'=>4),
 array('id'=>2,'name'=>'green','order'=>6),
 array('id'=>3,'name'=>'yellow','order'=>2),    
);

// $json is JSON version of the arrays in $arr
$json = json_encode($arr);

// show $json
echo $json . "\n";

// create arrays from JSON so it can be used in PHP easier
$obj = json_decode($json);

$color = 'blue';
$blue_order = array_filter($obj, function($i) use ($color) { return $i->name == $color; })[0]->order;

echo "Blue Order: " . $blue_order;

You may be able to use array_filter to help this become a one-liner. I included the json_decode and json_encode so I could have a complete example.