我不知道如何使我的匹配系统正常工作

Question

In my code, I am doing a matching system where you have two lists and the code adds one to a variable for every item in the list that is in the same index and the same item as the other list otherwise it adds one to the other variable it then puts both of the numbers in a list and prints the list.

def report(ticket,winner):
kiss = []
Love = []
x = 0
y = 0 
for number in ticket:
    if number in winner:
        x +=1
    elif ticket not in winner:
            y += 1
kiss.append(x)
kiss.append(y)
print kiss

an error is like this the input is, report([1,2],[1,2,3]) I want it to add two to the x becuase two of them are in thr correct place and are the same then it needs to add one to the y because its there and not matching but it gives me out: [2,0] also if I put in report([1,3],[1,2,3]) it gives me [2,0] even thoue there not in the same index. That output should be [1,2].

Answer 1

Based on the logic you describe there are a few problems that your code needs to implement. Mainly, in python the in operator checks if an item exists anywhere in a list , so for your examples that will always be True and you get that unexpected output.

Instead we want to check each item in the ticket list against each item in the winner list at the same index , so we must specify the index when checking each number.

Try this:

def report(ticket,winner):
    kiss = []
    Love = []
    x = 0
    y = 0 

    # because we are checking different length lists, set ticket to longest list
    if len(ticket) > len(winner):
        pass
    elif len(winner) > len(ticket):
        temp = ticket
        ticket = winner
        winner = temp

    for i, number in enumerate(ticket):
        try:
            if winner[i] == number:
                x+=1
            else:
                y+=1
        except IndexError:
            y+=1

    kiss.append(x)
    kiss.append(y)
    print kiss

l1 = [1,2]
l2 = [1,2,3]
report(l1, l2) # prints [2, 1]

l1 = [1,3]
l2 = [1,2,3]
report(l1, l2) # prints [1, 2]

Are these your expected outputs?

Hope this helps.

Answer 2

Here's a slightly shorter version using zip .

def report(ticket, winner):
    z = sum(1 for x, y in zip(ticket, winner) if x == y)
    return [z, max(len(ticket), len(winner)) - z]