列表（数组）中某个范围内的随机样本| Python 3.x

Question

I have a list with many characters in it like such:

list = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q',
        'r','s','t','u','v','w','x','y','z','1','2','3','4','5','6','7','8','9',
        '0'," ",'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P',
        'Q','R','S','T','U','V','W','X','Y','Z']

I want the program to randomly pick 8 characters within the first 26 (lowercase letters) items in my list. I will not delete or separate the other items in this array as I need them later for a similar thing.

I am somewhat new to programming and I prefer a simple solution, although I am not stopping you from putting something more complex out there for others to see.

Thanks in advance!

Answer 1

您可以切片该数组以对其进行采样。

random.sample(seq[:26], k=8)

Answer 2

Firsty you need the random module :

import random

Then I would use this solution:

your_list = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q',
        'r','s','t','u','v','w','x','y','z','1','2','3','4','5','6','7','8','9',
        '0'," ",'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P',
        'Q','R','S','T','U','V','W','X','Y','Z']

first_26_characters = your_list[0:26] # get items from 0 to 26 in new list
random.shuffle(first_26_characters) # shuffle new list
random_8_characters = first_26_characters[0:8] # get first 8 characters because after shuffle they are random

I hope this helps!