正则表达式匹配重复相同的单词或其中的一部分

Question

I give up: I simply can not find a solution to the problem. I've already checked for hours on stack overflow site but I can not find a solution. I have these strings:

table-2 table
table-4 seat
table-4 seat table-3

I want to use a regular expression to see if it already contains 'table-' or 'table' or 'tabl' or 'tab' ...

(?).test(string) === true only in Example N.2. How can I do that?

This was a attempt:

/\b([a-z(-0-9)?]+)\b(?=.*(\b)+)/g

Answer 1

This code snipped passes your test criteria:

[
  'table-2 table',
  'table-4 seat',
  'table-4 seat table-3',
].forEach(word => {
  console.log(word, !/(tabl?e?\-?).*?\1/.test(word));
})

UPDATE For the case if there is no exact word available (see comment below) it is possible to just check for some existence of some repeated substring that by itself forms a kind of word. In this case test may look like: !/\\b(\\S+)\\b.*?\\1/.test(word) , but of course exact solution may be different depending on actual task.