从数组中插入多行

Question

I need help to insert data into mysql. I am unable to find the problem in the code below why data is not inserted into database. When I am submitting the form this message comes : Notice: Undefined variable: asd in...

<?php
$q = mysql_query("select `cus_id`, `date`, `mobile`, 
    least(`t1`, `t2`, `t3`, `t4`) as min 
    from `table1`");

while($r = mysql_fetch_assoc($q)){

$asd = array(`cus_id` =>$r['cus_id'], 
             `mobile` =>$r['mobile'], 
             `date`   =>$r['date'], 
             `credit` =>$r['min']);
}

$sql = array();

foreach((array)$asd as $row){

$sql[] = '("'.mysql_real_escape_string($row['cus_id']).'", 
                                     '.$row['mobile'].', 
                                     '.$row['date'].', 
                                     '.$row['min_total'].'
           )';
}

$stmt = mysql_query('INSERT INTO `single` (`cus_id`, `mobile`, `date`, `credit`) 
                     VALUES '.implode(',', $sql));                                    

if(!$stmt){ 
echo "error". mysql_error();
}else{
$_SESSION['s']="Payment successfully saved";
header('location:final.php');
}
?>

Thanks for any help.

Answer 1

If I convert the above query into mysqli, then will the code be below:

<?php

$link = mysqli_connect('localhost', 'root', '', 'mumbai');
$q = "select `cus_id`, `date`, `mobile`, 
      least(`t1`, `t2`, `t3`, `t4`) as min 
      from `table1`";

$asd = array(); 
$result = mysqli_query($link, $q);
while($r = mysqli_fetch_assoc($result)){

$asd = array(`cus_id` =>$r['cus_id'], 
             `mobile` =>$r['mobile'], 
             `date`   =>$r['date'], 
             `credit` =>$r['min']);
}

$sql = array();

foreach((array)$asd as $row){

$sql[] = '("'.mysqli_real_escape_string($row['cus_id']).'", 
                                 '.$row['mobile'].', 
                                 '.$row['date'].', 
                                 '.$row['min_total'].'
       )';
}
$stmt = mysqli_prepare($link, "INSERT INTO single 
               (`cus_id`, `mobile`, `date`, `time`, `credit`) VALUES (?,?,?,?,?)");

mysqli_stmt_bind_param($stmt, 'isssi', implode(',', $sql));                  

mysqli_stmt_execute($stmt);

if(!$stmt){ 
echo "error". mysqli_error($link);
}else{
$_SESSION['s']="Payment successfully saved";
header('location:final.php');
}
?>

Answer 2

before your while loop add an $asd variable.

$asd = array();

while($r = mysql_fetch_assoc($q)){
....

then in your foreach you can remove the (array)

foreach($asd as $row){
....

no more Notice: Undefined variable: asd in...