重置具有不同值的JavaScript时间间隔？

Question

I have a small issue I can't seem to fix. I have a simple JavaScript code where I want to create a Interval that goes for a random amount of seconds, then after it finishes it should start over again and go for another random amount of seconds.

My code looks like this

 var selectedtimes = [3000, 5000, 15000, 10000] var randtimes = selectedtimes[Math.floor(Math.random() * selectedtimes.length)]; var sti = setInterval(function() { console.log("now") }, randtimes); function restartsti() { var restartinterval = setInterval(restartsti, selectedtimes[Math.floor(Math.random() * selectedtimes.length)]); } 

I tried to create a second function that would restart the interval but at the moment the interval takes only one random number and only uses that specific number as the duration.

To simplify my Node.js console should show "now" every randtimes seconds

Any solution to this?

I'm grateful for any help

Answer 1

setInterval is appropriate to use when the delay is intended to be consistent.

Since your delay is meant to be different each time, it's probably better to use setTimeout here:

 var times = [3000, 5000, 10000, 15000]; function start() { console.log("now"); var randTime = times[Math.floor(Math.random() * times.length)]; setTimeout(start, randTime); } start(); 

Answer 2

As Luke said, it's probably better to use setTimeout.

But if you want to keep using setInterval, you could stop the old one with clearInterval (providing the intervalID returned by the setInterval function) and start a new one :

var selectedtimes = [3000, 5000, 15000, 10000]

var randtimes = selectedtimes[Math.floor(Math.random() * selectedtimes.length)];


var sti = setInterval(function () {
    console.log("now")
    }, randtimes);

function restartsti() {
    clearInterval(sti);

    sti = setInterval(function() {
        console.log("now");
        restartsti()
    }, selectedtimes[Math.floor(Math.random() * selectedtimes.length)]);
}