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在Java中按升序对整数对列表进行排序?

[英]sorting a list of pair of integers in ascending order in java?

I am using the javafx pair class and trying to sort them using the second value. 我正在使用javafx对类,并尝试使用第二个值对它们进行排序。

  public static void main(String[] args)
   {
    List<Pair<Integer, Integer>> dist = new ArrayList<Pair<Integer, Integer>>();
    dist.add(new Pair <Integer,Integer> (4,54));
    dist.add(new Pair <Integer,Integer> (6,94));
    dist.add(new Pair <Integer,Integer> (7,4));
    dist.add(new Pair <Integer,Integer> (11,9));

    Collections.sort(dist, new ListComparator<>());

    System.out.println(dist);

     }

 public class ListComparator implements Comparator {

 @Override
public int compare(Pair<Integer, Integer> o1, Pair<Integer, Integer> o2) {
        return o1.getValue() - o2.getValue();

    }
  }

i keep getting the following errors and warning. 我不断收到以下错误和警告。

/tmp/java_izg9ZN/Main.java:34 : error : cannot infer type arguments for ListComparator Collections.sort(dist, new ListComparator<>()); /tmp/java_izg9ZN/Main.java:34错误 :无法推断ListComparator Collections.sort(dist, new ListComparator<>());类型参数Collections.sort(dist, new ListComparator<>());
reason: cannot use ' <> ' with non-generic class ListComparator 原因:不能对非通用ListComparator使用' <> '

/tmp/java_izg9ZN/ListComparator.java:21 : error : ListComparator is not abstract and does not override abstract method compare(Object,Object) in Comparator public class ListComparator implements Comparator { /tmp/java_izg9ZN/ListComparator.java:21错误ListComparator 不是 抽象的 ,并且不覆盖Comparator public class ListComparator implements Comparator {抽象方法compare(Object,Object)public class ListComparator implements Comparator {

/tmp/java_izg9ZN/ListComparator.java:23 : error : method does not override or implement a method from a supertype @Override /tmp/java_izg9ZN/ListComparator.java:23错误 :方法 覆盖或通过超类型@Override实现方法

i have no idea what i am doing wrong because i example i looked at to do this did exactly the same thing so i really dont know what i have done wrong. 我不知道我在做什么错,因为我举个例子,我看着这样做完全一样,所以我真的不知道我做错了什么。 please help! 请帮忙! thanks 谢谢

Your code has two problems . 您的代码有两个问题 First you call: 首先您致电:

Collections.sort(dist, new ListComparator<>());

So you tell Java to use a ListComparator which infers the type by itself (diamond operator <> ). 因此,您告诉Java使用一个ListComparator ,该ListComparator自己推断类型(菱形运算符<> )。

However your ListComparator class is not generic . 但是,您的ListComparator不是通用的 It does not expect any type arguments, like a String for example, you don't write String<...> . 它不期望任何类型参数,例如String ,您不要编写String<...>

You could fix this by making ListComparator generic, working on the elements of the List for example: 您可以通过使ListComparator通用化来解决此问题, ListComparator ,处理List的元素:

public class ListComparator<E> implements Comparator<E> {
    // Compare E elements ...
}

However it seems that you rather want a non-generic ListComparator which is fixed to comparing Pair<Integer, Integer> elements. 但是,您似乎想要一个非通用的 ListComparator ,它固定用于比较Pair<Integer, Integer>元素。 In that case remove the diamond operator: 在这种情况下,请删除菱形运算符:

Collections.sort(dist, new ListComparator());

The second problem is that you use raw-types for the Comparator instead of telling him the type of the objects that will be compared. 第二个问题是,您对Comparator使用原始类型 ,而不是告诉他将要比较的对象的类型。

Because of that the compiler expects at reading @Override that your compareTo methods matches the signature written in Comparator : 由于编译器预计在读@OverridecompareTo方法写在签名匹配Comparator

public int compareTo(Object o1, Object o2)

And not 并不是

public int compareTo(Pair<Integer, Integer> o1, Pair<Integer, Integer> o2)

You fix this by explicitly telling Comparator what to use instead of using raw-types : 您可以通过明确告诉Comparator使用什么而不是使用raw-types来解决此问题:

public class ListComparator implements Comparator<Pair<Integer, Integer>> {
    // Compare Pair<Integer, Integer> elements ...
}

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