将列表中的元素转换为haskell中的int？

Question

I am trying to make a function, and I need to specify what happens if the list has only 1 element. I want the function to return the element, but I don't know how to convert the element to an Int . Any help? I've tried round , frominteger , realtofrac , but nothing worked.

pMaiore :: Ord a => [a] -> Int

pMaiore [x]=                                      --give x but converted to Int
pMaiore (x:xs:xss)= if x>=xs then pMaiore(x:xss)
                    else  pMaiore(x:xss)          --when x<xs

Answer 1

How about this?

pMaiore :: (Ord a, Integral a) => [a] -> Int

pMaiore [x]= fromIntegral x              --give x but converted to Int
pMaiore (x:xs:xss)= if x>=xs then pMaiore(x:xss)
                    else  pMaiore(x:xss)          --when x<xs

If you want to convert an a into an Int you have to have some connection between them. One way is to use a typeclass. If you know that a is going to be a floating point then you can use RealFrac instead, and then the round function will work.