日期与strtotime无法正常工作-PHP

Question

I can't get this date with strtotime function to work properly. I need to convert the date to display to "d/m/Y". I'm getting the date off the database correctly but it does not convert to my new date format, instead it just echoes everything with the date inside the $row[saleDate].

Here's the code:

    echo "<tr><td class='contentTd'> $row[saleNumber] </td>
            <td class='contentTd'> $row[saleValue] </td>
            <td class='contentTd'> $row[paymentMethod] </td>
            <td class='contentTd'> $row[sellerName] </td>
            <td class='contentTd'> date('d/m/Y', strtotime($row[saleDate])); 
            </td></tr>";

Could you help me out please?

Answer 1

Use concatenation to show the date..

      echo "<tr><td class='contentTd'> $row[saleNumber] </td>
        <td class='contentTd'> $row[saleValue] </td>
        <td class='contentTd'> $row[paymentMethod] </td>
        <td class='contentTd'> $row[sellerName] </td>
        <td class='contentTd'>".' date('d/m/Y', strtotime($row[saleDate]);'. 
        "</td></tr>";

Answer 2

我认为您忘记了date（）函数或strtotime（）函数

Answer 3

I've found the error: Missing quotes inside the strtotime function.

echo "<tr><td class='contentTd'> $row[saleNumber] </td>
            <td class='contentTd'> $row[saleValue] </td>
            <td class='contentTd'> $row[paymentMethod] </td>
            <td class='contentTd'> $row[sellerName] </td>
            <td class='contentTd'>" . date('d/m/Y', strtotime("$row[saleDate]")) . "</td></tr>";

Now it's working fine!