[英]Pygame Simple Movement: Enemy mimicking player movement and also retracing steps
I want to use the movement method of my player class and have the enemy copy player movements. 我想使用玩家类的移动方法,并让敌人复制玩家的移动。 I want the enemy to basically follow the player until a certain condition is met for example 3 minutes have passed, after which I would like the enemy to retrace all its steps.
我希望敌人基本上跟随玩家,直到满足特定条件(例如3分钟)为止,之后我希望敌人回撤其所有步骤。 Below is my movement method in the player's class
以下是我在球员课堂上的移动方法
class PacMan(pygame.sprite.Sprite):
def __init__(self, x, y, radius):
super().__init__()
self.image = pygame.Surface([radius, radius])
self.image.fill([250, 250, 0])
self.rect = self.image.get_rect()
self.rect.x = x
self.rect.y = y
self.queue = [-speed1, 0]
self.direction = [-speed1, 0]
def change_direction(self, x, y):
self.queue = [x, y]
def move(self, level):
self.rect.x += self.queue[0]
self.rect.y += self.queue[1]
hitlist = pygame.sprite.spritecollide(self, level.wall_list, False)
if hitlist:
self.rect.x -= self.queue[0]
self.rect.y -= self.queue[1]
self.rect.x += self.direction[0]
self.rect.y += self.direction[1]
seclist = pygame.sprite.spritecollide(self, level.wall_list, False)
if seclist:
self.rect.x -= self.direction[0]
self.rect.y -= self.direction[1]
else:
self.direction[0] = self.queue[0]
self.direction[1] = self.queue[1]
if self.rect.x < -pacman_length:
self.rect.x = board_dimensions[0] - wall_length
self.rect.y = self.rect.y
if self.rect.x > board_dimensions[0]:
self.rect.x = wall_length
Next the enemy class which won't function apart from going to the right 4 pixels at a time 下一个敌人类别,除了一次向右移动4个像素外不会起作用
class Ghost(pygame.sprite.Sprite):
def __init__(self, x, y, color,):
super().__init__()
self.color = color
self.image = pygame.Surface([pacman_length, pacman_length])
self.image.fill(color)
self.rect = self.image.get_rect()
self.rect.x = x
self.rect.y = y
self.direction = [0, speed1]
self.moves = [False, True, True, False]
self.edible = False
self.wait = False
self.waitcount = 0
self.speed = speed1
def move(self, level):
status1 = False
status2 = True
self.rect.move_ip(4, 0)
x_change = 0
y_change = 0
for i in startingmovements:
print (i)
print(i[0])
print (i[1])
def change_color(self, color):
self.image.fill(color)
I use the while loop to actually make the characters move like so: 我使用while循环实际上使字符移动如下:
player.move(board)
for i in board.ghost_list:
i.move(board)
and 和
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
return
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
player.change_direction(-4, 0)
elif event.key == pygame.K_RIGHT:
player.change_direction(4, 0)
elif event.key == pygame.K_DOWN:
player.change_direction(0, 4)
elif event.key == pygame.K_UP:
player.change_direction(0, -4)
elif event.key == pygame.K_SPACE:
I understand that the code has an easy solution however I'm just having one of those times where I can't seem to grasp the answer. 我知道该代码有一个简单的解决方案,但是我遇到的那一次我似乎无法把握答案。 Any help given would really be appreciated
给予的任何帮助将不胜感激
A solution would be the putting a list as an attribute to your pac-man class. 一种解决方案是将列表作为pac-man类的属性。 For example,
self.steps=[]
. 例如,
self.steps=[]
。 The pac-man would list his coordinates so that the ghosts could track him. 吃豆人会列出他的坐标,以便鬼可以追踪他。
Implemented into your code: 实施到您的代码中:
class PacMan(pygame.sprite.Sprite):
def __init__(self, x, y, radius):
super().__init__()
self.image = pygame.Surface([radius, radius])
self.image.fill([250, 250, 0])
self.rect = self.image.get_rect()
self.rect.x = x
self.rect.y = y
self.queue = [-speed1, 0]
self.direction = [-speed1, 0]
#add some starting values
self.steps=[]
Now let's add a function to have pac-man list his steps. 现在,让我们添加一个函数,让pac-man列出他的步骤。
def update_steps():
#add current position
self.steps.insert(0,(self.rect.x,self.rect.y))
#delete old steps
del self.steps[:-1]
Now for the ghost function: 现在为鬼功能:
def update_pos(steps):
self.rect.x=steps[:-1[1]]
self.rect.y=steps[:-1[2]]
Also, make sure to update the ghost instead of the pac-man first. 另外,请确保先更新虚影而不是pac-man。
I hope this helps! 我希望这有帮助!
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.