根据属性值删除SQL Server表的XML列中的行
[英]Delete a row in a XML column of a SQL Server table based on attribute value
问题描述
I have a XML column in a SQL Server table. 
我在SQL Server表中有一个XML列。
The data looks like this: 数据如下所示：
<ColumnLayout>
<LayoutColumns>
<Column PropertyId="43" ColumnWidth="0" IsHidden="false" IsDefaultColumn="false" />
<Column PropertyId="12" ColumnWidth="0" IsHidden="false" IsDefaultColumn="false" />
<Column PropertyId="41" ColumnWidth="0" IsHidden="false" IsDefaultColumn="false" />
<Column PropertyId="16" ColumnWidth="0" IsHidden="false" IsDefaultColumn="false" />
<Column PropertyId="23" ColumnWidth="0" IsHidden="false" IsDefaultColumn="false" />
<Column PropertyId="94" ColumnWidth="0" IsHidden="false" IsDefaultColumn="false" />
<Column PropertyId="98" ColumnWidth="0" IsHidden="false" IsDefaultColumn="false" />
</LayoutColumns>
</ColumnLayout>
I want to delete a column node which contains PropertyId = 43 . 我想删除一个包含PropertyId = 43的列节点。
How to query that and update the XML column in that table? 如何查询该表并更新该表中的XML列？
1 个解决方案
解决方案1
3 已采纳 2017-10-24 11:47:47
Just use the XQuery .modify() method with a delete command: 只需将XQuery .modify()方法与delete命令一起使用：
UPDATE dbo.YourTable
SET Content.modify('delete /ColumnLayout/LayoutColumns/Column[@PropertyId=43]')
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