PHP 5.2.6 中的年龄计算

Question

I am facing a problem while calculating age saved in the database. I obtained help from a user of this site and he gave me the proper output file but i ran into anoth issue. The solution is made for newer php version but the php version i have is 5.2.6. Any help in this method will be highly appreciated. Here is the code he provided me

if(!empty($row11['dob'])){ 
            $birthdate = new DateTime($row11['dob']);
            $today     = new DateTime('today');
            $ag = $birthdate->diff($today)->y;
            $mn = $birthdate->diff($today)->m;
            $dy = $birthdate->diff($today)->d;              
        }else{
            $ag = 0; $mn=0; $dy=0;
        }   

I am also attaching the original file so that you can help me better. Please do note that i am using php 5.2.6 for this purpose. Any prompt help in this regard will be highly appreciated. Thanks

Here is the link to Original File

Answer 1

Maybe I can help. Datetime->diff was introduced in PHP 5.3, so you'd need a workaround.

Not the neatest, but definitely a quick way of doing it is to substract the current date with the birthdate divided by the number of years that passed. This would look something like:

$birthdate = new DateTime($row11['dob']);
$today = new DateTime('today');
$year = round(($today->format('U') - $birthdate->format('U')) / (60*60*24*365));

For months, the situation becomes more complicated, but based on the example it doesn't seem like you need much more detail than this. If you want to account for leapyears I'd suggest extending the formula.