减少 std::cout 中的 << 运算符链

Question

Is there any way to reduce the chain of << operator from the statements like following ?

std::cout << var1 << "!=" << var2;

printf() may be an option but anything else?

Because as the number of the operator << increases so the running time too.

Is it possible to efficiently reduce the << chain ?

Answer 1

No, this is not possible.

The fundamental reason is that operator<<(const char*) and operator<<(int) are both simple. In fact, they're so simple that they're likely to be inlined.

printf(const char* format, ...) on the other hand is a very complex function as it needs to deal with many possible format specifiers, and it also has a variable argument list that it needs to parse.

Any other single function would have the same disadvantage of being so complex it can't be inlined.