将日期时间转换为ISO格式

Question

I have a date in format dd.MM.yyyy HH:mm:ss and I need to convert it to ISO format, but it's not working correctly. Here is my code:

let date = '12.01.2016 0:00:00'; //12 January 2016
let parsedDate = moment(date, 'dd.MM.yyyy HH:mm:ss')
console.log(parsedDate.toISOString()); //result is 2016-12-31T23:00:00.000Z

example2:

let date = '12.01.2016 0:00:00'; //12 January 2016
let parsedDate = new Date(date)
console.log(parsedDate.toISOString()); //result is 2016-11-30T23:00:00.000Z

Where is the problem? Why do I get different results?

Answer 1

Your format parameter is wrong, use 'DD.MM.YYYY H:mm:ss' instead.

There is no lowercase dd , use uppercase DD for day of month and use uppercase YYYY for year instead of lowercase yyyy .

Please note that toISOString() :

Note that .toISOString() always returns a timestamp in UTC, even if the moment in question is in local mode. This is done to provide consistency with the specification for native JavaScript Date . toISOString() , as outlined in the ES2015 specification .

 let date = '12.01.2016 0:00:00'; //12 January 2016 let parsedDate = moment(date, 'DD.MM.YYYY H:mm:ss') console.log(parsedDate.toISOString()); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.19.1/moment.min.js"></script> 

Answer 2

In the second example, the parsed date results in December 1, 2016 0:00:00 (GMT+1)

When you output toISOString() it gives you the GMT time, which is 1 hour earlier, hence the November 30, 2016 23:00:00

Answer 3

Look this link https://www.w3schools.com/js/js_date_formats.asp , paragraph 'ISO Dates'

Omitting T or Z in a date-time string can give different result in different browser.

Answer 4

I just tried using moment.js and it seems you used a mask as you'd use in C# for example. Moment.js uses capitals in the date parts.

let date = '12.01.2016 0:00:00'; //12 January 2016
let parsedDate = moment(date, 'DD.MM.YYYY HH:mm:ss');
console.log(parsedDate.toISOString()); //result is 2016-01-11T23:00:00.000Z

The Date.parse() function requires another kind of input.