[英]Sort a list of strings by second-to-last character
I need to sort a list of strings using character comparison starting with penultimate element moving down to the beginning of string (for equal characters).我需要使用字符比较对字符串列表进行排序,从倒数第二个元素向下移动到字符串的开头(对于相等的字符)。 so basically I need to get this所以基本上我需要得到这个
in_ = ['message', 'essagem', 'ssageme', 'sagemes', 'agemess', 'gemessa', 'emessag']
result = ['emessag', 'essagem', 'sagemes', 'message', 'ssageme', 'agemess', 'gemessa']
# sorted on second to last character in each string
Is this what you want?这是你想要的吗? If yes, make that penultimate letter the key for the sort()
function.如果是,则将该倒数第二个字母作为sort()
函数的键。
a = ['message', 'essagem', 'ssageme', 'sagemes', 'agemess', 'gemessa', 'emessag']
a.sort(key=lambda x:x[-2])
print(a)
Output:输出:
['emessag', 'essagem', 'sagemes', 'message', 'ssageme', 'agemess', 'gemessa']
Just to add something alternative to Miraj50's answer: You can do it using itemgetter
too in a bit cleaner/faster way .只是为 Miraj50 的答案添加一些替代方法:您也可以使用itemgetter
以更清洁/更快的方式来完成。
from operator import itemgetter
in_list = ['message', 'essagem', 'ssageme', 'sagemes', 'agemess', 'gemessa', 'emessag']
result = sorted(in_list, key=itemgetter(-2))
print(result)
output:输出:
['emessag', 'essagem', 'sagemes', 'message', 'ssageme', 'agemess', 'gemessa']
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