[英]Providing a Base Class Constructor
Is it necessary to always provide your base class with a constructor? 是否有必要始终为您的基类提供构造函数? For example if I had the following base class, and then some derived classes. 例如,如果我有以下基类,然后是一些派生类。
class Animal
{
public:
//Is this constructor necessary?
Animal();
virtual ~Animal();
};
class Zebra: public Animal
{
public:
Zebra();
~Zebra();
};
class Elephant: public Animal
{
public:
Elephant();
~Elephant();
};
Assuming that I am creating Animal pointers and then dynamically allocating new Zebra and Elephant objects. 假设我正在创建Animal指针,然后动态分配新的Zebra和Elephant对象。 If I never intend to create an Animal object, then is there any actual need to explicitly create an Animal constructor? 如果我从不打算创建一个Animal对象,那么是否真的需要显式创建一个Animal构造函数?
You don't need to explicitly provide constructor. 您不需要显式提供构造函数。 A default one is generated (if you don't provide other constructor). 生成默认值(如果您不提供其他构造函数)。
so 所以
class Animal
{
public:
virtual ~Animal();
};
is sufficient. 足够了。
Derived classes constructors would call Base class constructor (explicitly of implicitly). 派生类构造函数将调用Base类构造函数(显式地隐式)。
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