jQuery比较两个数组对象以拥有一个最终的数组对象

Question

Could anyone help on below scenario? I have two array objects to compare based on model and serial and need to come out with one result only. Please refer to below sample. Thanks.

ArrayObject1 = [{model:'M1', serial:'S1', file:'F1', other:null},
                {model:'M2', serial:'S2', file:'F2', other:null}];

ArrayObject2 = [{model:'M1', serial:'S1', file:null, other:'F3'},
                {model:'M3', serial:'S3', file:null, other:'F4'}];

ExpectedResult = [{model:'M1', serial:'S1', file:'F1', other:'F3'},
                 {model:'M2', serial:'S2', file:'F2', other:null},
                 {model:'M3', serial:'S3', file:null, other:'F4'}];

Answer 1

I don't think jquery offers an easy method to solve your problem. And this is my solution:

 var arr1 = [ { model: "M1", serial: "S1", file: "F1", other: null }, { model: "M2", serial: "S2", file: "F2", other: null } ]; var arr2 = [ { model: "M1", serial: "S1", file: null, other: "F3" }, { model: "M3", serial: "S3", file: null, other: "F4" } ]; var arr3 = arr1.concat(arr2); var result = []; arr3.forEach(function(item1, index){ var arr4 = result.filter(function(item2, index){ return item1.model === item2.model; }); if (arr4.length === 1) { for(var prop in item1){ if (item1.hasOwnProperty(prop)) { arr4[0][prop] = (item1[prop] || arr4[0][prop]); } } }else{ result.push(item1); } }); console.log(result); 

This only works for the situation when there are atmost 2 models with same model name to merge, because if there are three 'M1' and two of them have none-null 'file', then i don't know which to choose..

Answer 2

var ExpectedResult = [];
//loop through either of the object array. Since they are of same length, it wouldn't matter which one you choose to loop though.
 for(var i = 0; i < ArrayObject2.length; i++) {
   //check to see if the array element(which are objects) have the same model property
   if(ArrayObject2[i].model === ArrayObject1[i].model){
     //if they are the same, starting switching the values of the file and other properties in either one of the array 
     //I choose ArrayObject2, it won't matter which one you decide to use

     //this chooses which is truthy between file property of ArrayObject2 at index i and file property of ArrayObject1 at index i and assigns it to the file property of ArrayObject2 at index i
     ArrayObject2[i].file = ArrayObject2[i].file || ArrayObject1[i].file;

      //this chooses which is truthy between other property of ArrayObject2 at index i and other property of ArrayObject1 at index i and assigns it to the other property of ArrayObject2 at index i
     ArrayObject2[i].other = ArrayObject2[i].other || ArrayObject1[i].other;

     //push the ArrayObject2 at position i into the ExpectedResult array
     ExpectedResult.push(ArrayObject2[i]);
   }
   //other wise; if the model property differs, just push the ArrayObject1 and ArrayObject2 at index i
   else {
     ExpectedResult.push(ArrayObject1[i]);
     ExpectedResult.push(ArrayObject2[i]);
   }
 }

 ExpectedResult;