有一个Java数组列表； 如何按每个数组的最后一个元素排序？

Question

I have a snippet of code which looks as follows:

List<int[]> v1v2weighting = new ArrayList<int[]>();

for(int i = 0; i < size; i++){
    for(int j = 0; j < size; j++){
        int[] a = {i,j,graph[i][j]};
        v1v2weighting.add(a);
    }
}

After this concludes, I have a list of 3-element arrays, where the final element in each array is the weighting. I'd now like to sort this list by the weighting, ie arrive at a finished list where for every element e, e_i[2] ≤ e_(i+1)[2]. Is there a simple way to perform an operation like this in Java? I've come across collections.sort() while looking for a solution, but this seems to only work in the event that I'm dealing with a list of comparables such as integers. Any help is appreciated.

Answer 1

For sorting List in Java 1.7, you may use the following code segment.

Collections.sort(v1v2weighting, new Comparator<int[]>() {
    public int compare(int[] o1, int[] o2) {
        return Integer.compare(o1[2], o2[2]); // suppose all your arrays has at least 3 elements
    }
}

In fact, you may implement any sorting mechanism using this method.