[英]PHP Mysql - adding an empty row can't figure it out
Here is the table code - when this is printed out the has one empty row at the bottom. 这是表格代码-打印出来时,表格底部有一个空行。 I am not sure why the last row is added? 我不确定为什么要添加最后一行? Is it perhaps the if else statement? 也许是if陈述吗?
<?php
$row = mysql_fetch_array($result);
if ($row['Price'] == '0.00') {
echo "<TABLE width='100%'>\n";
echo "<TR><TD id=tblrowsHead2>Item</TD><TD id=tblrowsHead2>Size</TD><TD
id=tblrowsHead2>Contact</TD></TR>\n";
for ($i = 0; $i < $numofrows; $i++) {
$row = mysql_fetch_array($result); //get a row from our result set
if ($i % 2) { //this means if there is a remainder
echo "<TR bgcolor=\"#E6E6FA\">\n";
} else { //if there isn't a remainder we will do the else
echo "<TR bgcolor=\"white\">\n";
}
echo "<TD id=Size>" . $row['Item'] . "</TD><TD id=Size>" . $row['Size']
. "</TD>
<TD id=Price>Contact Us</TD>\n";
}
} else {
echo "<TABLE width='100%'>\n";
echo "<TR><TD id=tblrowsHead2>Item</TD><TD id=tblrowsHead2>Size</TD><TD
id=tblrowsHead2>Price</TD></TR>\n";
for ($i = 0; $i < $numofrows; $i++) {
$row = mysql_fetch_array($result); //get a row from our result set
if ($i % 2) { //this means if there is a remainder
echo "<TR bgcolor=\"#E6E6FA\">\n";
} else { //if there isn't a remainder we will do the else
echo "<TR bgcolor=\"white\">\n";
}
echo "<TD id=Size>" . $row['Item'] . "</TD><TD id=Size>" . $row['Size']
. "</TD>
<TD id=Price>$" . $row['Price'] . "</TD>\n";
}
}
//now let's close the table and be done with it
echo "</TABLE>\n";
?>
Try this code instead: 请尝试以下代码:
<?php
$row = mysql_fetch_array($result);
$i = 0;
if ($row['Price'] == '0.00') {
echo "<TABLE width='100%'>\n";
echo "<TR><TD id=tblrowsHead2>Item</TD><TD id=tblrowsHead2>Size</TD><TD id=tblrowsHead2>Contact</TD></TR>\n";
do {
if ($i % 2) { //this means if there is a remainder
echo "<TR bgcolor=\"#E6E6FA\">\n";
} else { //if there isn't a remainder we will do the else
echo "<TR bgcolor=\"white\">\n";
}
echo '<TD id=Size>'.$row['Item'].'</TD><TD id=Size>'.$row['Size'].'</TD>';
echo "<TD id=Price>Contact Us</TD></TR>\n";
$i++;
} while ($row = mysql_fetch_array($result)); //get a row from our result set
} else {
do {
if ($i % 2) { //this means if there is a remainder
echo "<TR bgcolor=\"#E6E6FA\">\n";
} else { //if there isn't a remainder we will do the else
echo "<TR bgcolor=\"white\">\n";
}
echo '<TD id=Size>'.$row['Item'].'</TD><TD id=Size>'.$row['Size'].'</TD>';
echo "<TD id=Price>$" . $row['Price'] . "</TD></TR>\n";
$i++;
} while ($row = mysql_fetch_array($result)); //get a row from our result set
}
//now let's close the table and be done with it
echo "</TABLE>\n";
When you using the mysql_fetch_array at the first line of for-loop , you will lost the first record of your data-table, so you will have an empty line at the end 在for-loop的第一行使用mysql_fetch_array时,您将丢失数据表的第一条记录,因此末尾将有一个空行
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