排序顺序和查找重复模式

Question

      //other arrays sequences sample
      {23,45,38, 9,43,25,18}
      {21,33,22, 5, 1,44,16}
      {28,24, 5,42,15,49,41}
      {43,18,50,29,22,32,25}
      {33,38,27,35,25, 1,12}
      {21,33,22, 5, 1,44,16}
      {28,24, 5,42,15,49,41}

I have a little project where i have a list of sequences and i would like to have them rearranged from small to large and reprinted for use to find repeating sequences and show how many time each sequence repeats

Now I wrote a small code sorting the sequences from small to large with the aid of a friend in order to solve the first problem.

But I would like it to work with multiple sets and arrange each set and print them on there own line, In order for me to find the repeating patterns

Yet every time i change the {int} to accommodate more sequences the code fails

public class Main {
    public static void main(String args[]) {
        int x[] = {37, 36, 20, 23, 44, 27, 24};

        for (int y = 0; y <= x.length; y++) {
            for (int z = 0; z <= x.length - 2; z++) {
                if (x[z] > x[z + 1]) {

                    int temp = 0;
                    temp = x[z];

                    x[z] = x[z + 1];
                    x[z + 1] = temp;
                }
            }
        }

        for (int y = 0; y < x.length; y++) {
            System.out.print(x[y]);
        }
    }
}

as part of the second problem finding the repeating sequence i'm looking into dis post and busy reworking to see if it will work.

Yet as far as i see it will find the repeating number and not sequence witch is where i'm stuck.

How to find repeating sequence of Integers in an array of Integers?

I'm still new to java and any aid will be appreciated Kind Regards Deon

Answer 1

I suggest you split this in two separate questions. I will now try to answer to the sorting problem, however, I'm not quite sure if I understand your problem here.

You implemented the bubble sort . You can see in the linked Wikipedia article how this is correctly implemented. Basically there is a do-while loop as the outer loop.

Alternatively, you could also use Java's Arrays#sort

EDIT

You can create a two dimensional array for your sequences like this:

  int[][] seq = {
      {23,45,38, 9,43,25,18},
      {21,33,22, 5, 1,44,16},
      {28,24, 5,42,15,49,41},
      {43,18,50,29,22,32,25},
      {33,38,27,35,25, 1,12},
      {21,33,22, 5, 1,44,16},
      {28,24, 5,42,15,49,41}
  };

Then, you can iterate over seq and sort each contained array individually:

for(int i = 0; i < seq.length; i++) {
  int[] x = seq[i];
  // sort x
}

Answer 2

您不能只使用Arrays.sort（x）对数组进行排序。

Answer 3

Thanks Hage, It's small but I learned a lot Here is the working code

    public class Main {

        public static void main(String[] args) {
            int[][] seq={{ 42, 22, 40, 1, 11, 5, 43 },
                         { 13, 11, 18, 45, 3, 44, 19 },
                         { 46, 1, 32, 47, 35, 7, 36 },
                         { 48, 21, 38, 29, 3, 12, 11 },
            };

            for (int i=0; i < seq.length; i++) {
                int[] x=seq[i];

                Arrays.sort(x);
                for (int number : x) {
                        System.out.print(number  + " ");}
                        System.out.print("\n");
                    }
                }
            }