替换 JavaScript 中的中间 n 个字符

Question

I have a phone number and I want to display it like censored form. For example I have: +923451234567

I want to display it like: +923*******67

Str.replace function will be used, but how:

var str = '+923451234567'
str.replace(i_Dont_Know_What, '*');

So in this case string contains 13 characters. And I want to replace 5th-11th character with " * "

I have found this somewhere, but this is not what I want.

var str = "name(replace these parenthesis by @)domain.com";
var patt1 = /\(.*@\)/i;
document.write(str.replace(patt1,"@"));

How would I achieve this?

Answer 1

Nice and simple one line replace with a substring match, no need for a messy regex here.

 var str = '+923451234567'; console.log(str.replace(str.substring(4,11), "*******"));

Answer 2

有多种方法，一种方法是简单的 reg 表达式

 console.log("+923451234567".replace(/(\\+\\d{3})\\d{7}/,"$1*******"))

Answer 3

regex to keep 3 num characters at the beginning and 2 at the end

regex explanation: https://regex101.com/r/xR6pRD/1

 var str = '+923451234567' str = str.replace(/(\\+?\\d{3})(\\d+)(\\d{2})/g, function(match, start, middle, end) { return start + "*".repeat(middle.length) + end; }); document.write(str);

Answer 4

You could use a dynamic approach by giving the length and take an offset for shifting the replacement charcters.

 function replaceMiddle(string, n) { var rest = string.length - n; return string.slice(0, Math.ceil(rest / 2) + 1) + '*'.repeat(n) + string.slice(-Math.floor(rest / 2) + 1); }; console.log(replaceMiddle('+923451234567', 7)); console.log(replaceMiddle('+923451234567', 6)); console.log(replaceMiddle('+923451234567', 5)); console.log(replaceMiddle('+923451234567', 4)); console.log(replaceMiddle('+923451234567', 3)); console.log(replaceMiddle('+923451234567', 2)); console.log(replaceMiddle('+923451234567', 1));

 .as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 5

First we get the substring to be replaced:

//you can use variables here too
var substringToBeReplaced = num.substring(4, 11); //4512345

then we replace the substring in the string:

var str = '+923451234567'
str.replace(substringToBeReplaced, '*******'); //result will be +923*******67

you can use another range instead of 4 - 11 if you want other set of numbers to be replaced.

Answer 6

 var str = '+923451234567'; var lol = str.replace(/^(\\+?[\\d]{3})\\d+(\\d{3})$/g,"$1*****$2"); console.log(lol);

Answer 7

I would just reconstruct a new string like so

replaceWithStar(index1,index2, str) {
    return str.substr(0, index1) + '*******'+ str.substr(index2, str.length);
}

Answer 8

try it is a complete method.

 setStar(val) {
        let value = val.split('');
        let centerVal = value.slice(3,7);
        return value.slice(0,3).join("") + centerVal.map(()=> "*").join("") + value.slice(7,11).join("");
      }

i hope useful.