[英]Python get items in a list of that are not in a list
I have a list with countries: countries = ['United States', 'Canada', 'France', 'Japan', 'Turkey', 'Germany', 'Ghana', 'Hong Kong', 'United Kingdom']
我有一个国家名单:国家= ['United States', 'Canada', 'France', 'Japan', 'Turkey', 'Germany', 'Ghana', 'Hong Kong', 'United Kingdom']
i want to get all the lines that do not contain any country. 我希望获得所有不包含任何国家/地区的行。 this is my code: 这是我的代码:
with open('file.txt') as f:
lines = f.readlines()[1:5]
a = [line.split(':') for line in lines]
for country in countries:
for line in a:
if country not in line:
print(line)
print(line) prints all the lines instead of printing those that do not contain countries print(line)打印所有行而不是打印那些不包含国家/地区的行
That's what the any()
and all()
functions are for. 这就是any()
和all()
函数的用途。
countries = ['United States', 'Canada', 'France', 'Japan', 'Turkey', 'Germany', 'Ghana', 'Hong Kong', 'United Kingdom']
with open('file.txt') as f:
lines = f.readlines()[1:5]
a = [line.split(':') for line in lines]
for line in a:
if not any(country in line for country in countries):
print(line)
You can try this: 你可以试试这个:
data = [i.strip('\n').split(":") for i in open('filename.txt')]
countries = ['United States', 'Canada', 'France', 'Japan', 'Turkey', 'Germany', 'Ghana', 'Hong Kong', 'United Kingdom']
final_data = [i for i in data if not any(b in countries for b in i)]
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