SQL数据透视-如何获取要透视的列之间的所有可能组合

Question

This is my source table (pivot_dummy):

and I need to pivot it by Parameter_type but need all possible combinations between Parameter_val's. Something like this

I am using this code to get it done:

SELECT nct_id, [Asset],[Indication], rowid
FROM (SELECT nct_id,Parameter_val,parameter_type, rowid
      FROM (Select *,
                   Row_Number() Over (Partition By nct_id,Parameter_type ORDER BY nct_id) RowId 
            from [dbo].[pivot_dummy]
           ) a 
     ) s
Pivot (
    max(parameter_val)
        for Parameter_type in ([Asset], [Indication])
    ) as pivottable

but this code results in following:

Can someone please help?

Answer 1

From what I can tell, you don't want a pivot at all. Simply a join :

select pd1.nct_id, pd1.parameter_value as asset, pd2.parameter_value as indication
from pivot_dummy pd1 join
     pivot_dummy pd2
     on pd1.nct_id = pd2.nct_id and
        pd1.parameter_type = 'Asset' and
        pd2.parameter_type = 'Indication';