[英]Aggregate function inside Case Statement
I am having some trouble with aggregate functions inside a case
statement. 我在
case
语句中的集合函数遇到了一些麻烦。 I want to write a query that will set field A to N
if it is equal to the minimum date of field A, or M
otherwise. 我想编写一个查询,如果它等于字段A的最小日期,则将字段A设置为
N
,否则将字段M
设置为N
Sample Code: 样例代码:
SELECT *, CASE
WHEN Field_A = MIN(FIELD_A) THEN 'JN'
ELSE 'JP'
END AS JUDI
FROM TABLE_1
GROUP BY *
I am not sure why the command runs but does not execute correctly. 我不确定为什么命令会运行但无法正确执行。 It labels all rows as
JN
in the JUDI
Field. 它将所有行标记为
JUDI
字段中的JN
。 How can I fix this? 我怎样才能解决这个问题?
I am running SQL Server 7. What I want to achieve is that in a list of rows with different dates it labels those with the earliest date with JN
and subsequent dates with JP
. 我正在运行SQL Server7。我想要实现的是,在具有不同日期的行列表中,它用
JN
标记最早的日期,而用JP
标记最早的日期。
Use window functions: 使用窗口功能:
SELECT t.*,
(CASE WHEN t.Field_A = MIN(t.FIELD_A) OVER () THEN 'JN'
ELSE 'JP'
END) AS JUDI
FROM TABLE_1 t;
You don't need aggregation over the entire table for this. 您不需要为此在整个表上进行聚合。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.