Python tkinter操作，用于从文本框中传递值

Question

Actually I have done a script for .docx operation. That script would count the total .docx files in the folder and give some reports. Now I plan to use a GUI operation on that. In my script I Put that folder which is presented in the python directory so it's working but I what I want here is, User will enter the path in textbox like "C:/user/app/data/folder_name" and when pressing of the submit button It will show the report. Here I attached the code

code:

import os
import glob
from docx import Document

from tkinter import *
def print_input():

    mypath = text_entry.get()
    files=0
    for name in os.listdir(mypath):
        if name.endswith('.docx'):
          files=files+1
    print("Total No of Files:",files)
    table=0
    for name in os.listdir(mypath):
         for word in glob.glob('*.docx'):
          doc=Document(word)
          for t in doc.tables:
            for ro in t.rows:
              if ro.cells[0].text=="ID" :
                table=table+1
    print("Total Number of Tables: ", table)

root = Tk()
Label(root, text="Enter Path").grid(row=0)

text_entry = Entry(root)
text_entry.grid(row=1, column=0)
Button(root, text='Submit', command=print_input).grid(row=3, column=0, sticky=W, pady=4)
mainloop()

This is my new code. But I have only one file in that folder and it consist 5 tables. This code giving 2 files and 312 tables. what can i do?

Answer 1

You can use the get() method of the Entry widget to get what the user has input.So something like this should work:

from tkinter import *
def get_path():
    #Something like this
    #replace your default path with the user's path
    mypath = text_entry.get()
    files=0
    for name in glob.glob(mypath):
    files=files+1
    print("Total No of Files:",files)

root = Tk()
Label(root, text="Enter Path").grid(row=0)
#Create text entry and add it to the window:
text_entry = Entry(root)
text_entry.grid(row=1, column=0)
#This button will call the get_path function when it is clicked
Button(root, text='Submit', command=get_path).grid(row=3, column=0, sticky=W, pady=4)
mainloop()

Edit:You could also use the Text widget to display your results when the same submit button is called