在bash中循环浏览一系列文件名

Question

I am trying to process some files in a loop. This version is kind of hard coded for testing but my problem is to get the full filename with variables and it looks good to me but the script hangs so obviously I did something silly. Can anyone help? Here is my script

File_numbers={1003,1004}
File_name=$Domain + "__" + $Domain + "_" + $i "__" + * +  ".ext"
Full_path=$Path + "/" + $Domain + "/" + $File_name

for i in $File_numbers; 
do echo $i; cat $Full_path; 
done

If someone has a more elegant solution that would be fine as well.

Update: I have changed my script as such (based on the issues pointed out by users)

#!/bin/bash

Path="aPath";
Domain="aDomain";
File_numbers="{1003,1004}"
Full_path=$Path"/"$Domain"/"

for i in $File_numbers; do find $Full_path -name "*"$i"*" | xargs cat; done

it seems that the variable is not recognized in this case

Answer 1

I would do (fixing a bunch of minor issues):

#!/bin/bash
Path="aPath"
Domain="aDomain"
File_numbers="[1003|1004]"
Full_path="$Path/$Domain/"

find $Full_path -name "*$File_numbers*" | xargs cat

So what I changed:

• no ; in bash !
• no need to loop on File_numbers. [1003|1004] means anything including 1003, or 1004.
• notice how -name " $File_numbers " contains everything within the ""
• Full_path: variables are usable within double quotes (").

Finally, I strongly suggest you do a quick google search and find a beginners guide to bash, it will save you a LOT of time! Invest now or waist time later!