遍历列表后更新字典的值

Question

I have the following:

tup_list=[("name1",2,3),("name6",54,6),("name4",4,6)]

my_dict={"name1": 0,"name2": 0,"name3": 0,"name4": 0,"name5": 0,"name6": 0}


def checker(tup_list,my_dict):
    for tup in tup_list: 
       if tup[0] in my_dict: 
          my_dict[0]+=1

I am looking to loop through tup_list, and if the key exists in my_dict, I want to add +1 to the value associated with that key in my_dict. I am getting errors and I am not sure how best to fix this.

Answer 1

You are getting error Because when you do :

for tup in tup_list: 
   if tup[0] in my_dict: 
      my_dict[0]+=1  #first check what you are increasing

Try to print(my_dict[0]) are you getting what you were expecting?

So you are increasing the value but where are you storing that changed stuff? For that, you have to tell dictionary to save that updated value of which key.

instead of :

  my_dict[0]+=1

Use:

my_dict[tup[0]]+=1

or

my_dict[item[0]]=value+1   #if you are iterating over dict 

Try this

def checker(tup_list,my_dict):
    for tup in tup_list:
        if tup[0] in my_dict:
            my_dict[tup[0]]+=1
    return my_dict

print(checker(tup_list,my_dict))

Detailed solution:

tup_list=[("name1",2,3),("name6",54,6),("name4",4,6),]

my_dict={"name1": 0,"name2": 0,"name3": 0,"name4": 0,"name5": 0,"name6": 0}


    def checker(tup_list,my_dict):
        for item in tup_list:
            for key,value in my_dict.items():
                if item[0]==key:
                    my_dict[item[0]]=value+1
        return my_dict

print(checker(tup_list,my_dict))

output:

{'name4': 1, 'name3': 0, 'name6': 1, 'name5': 0, 'name1': 1, 'name2': 0}