在这个程序中请解释输出

Question

void main()
{
    int a=5,*p,*c=NULL;
    printf("p=%u",p);    //OUTPUT p=3839036080
    printf("\nc=%u",c);  //OUTPUT c=0

}

Here we haven't assigned any address to p then why is it even printing anything? And c is assigned NULL so this means it stores the value as 0 ?

Answer 1

Here we haven't assigned any address to p then why is it even printing anything?

You called printf() , so it has to print something . The variable is uninitialized, so it prints whatever happened to be in the memory used to hold the variable.

And c is assigned NULL so this means it stores the value as 0?

Yes, NULL is a macro that expands to either 0 , (char *)0 , or something equivalent.