批处理脚本以读取和提取文本文件中的详细信息

Question

I need to copy a few files and folders to their respective destinations using a Windows batch script.

All the files and folders I am supposed to copy, are kept within a folder, SOURCE .

Example :

• folder: C:\\X\\Y\\Z\\SOURCE\\A
  
• file : C:\\X\\Y\\Z\\SOURCE\\A.txt
  
• file : C:\\X\\Y\\Z\\SOURCE\\B.txt
  
• folder: C:\\X\\Y\\Z\\SOURCE\\ZZZ

The destination paths of all the above are provided as text file contents, destination.txt .

Content of destination.txt :

C:\FinalDestination\D\A\...
C:\FinalDestination\N\A.txt
C:\FinalDestination\C\B.txt
C:\FinalDestination\U\ZZZ\...

Where three dots at the end signifies a directory, otherwise it's a file.

What I need to do in the above scenario is:

• Copy folder A from SOURCE to C:\\FinalDestination\\D\\
• Copy file A.txt from SOURCE to C:\\FinalDestination\\N\\
• Copy file B.txt from SOURCE to C:\\FinalDestination\\C\\
• Copy folder ZZZ from SOURCE to C:\\FinalDestination\\U\\

I don't know how to do it as I am pretty new to Windows command line.

I know XCopy is a command which can work for me, xcopy source destination , but I don't know how to extract the source and destination details.

Answer 1

Using an unchanged destination.txt and your supplied data, the following may help:

@Echo Off

Set "sD=C:\X\Y\Z\SOURCE"
Set "sF=destination.txt"

For /F "UseBackQ Delims=" %%A In ("%sF%"
) Do For %%B In ("%%~fA.") Do echo=XCopy/IY "%sD%\%%~nxB" "%%~dpA." 2>Nul
Pause

You need only modify the content of the variables at lines 3 and 4

Note :

I have currently made it so that nothing is copied, just the commands output to your screen. If you are happy with the output remove echo= from line 7 and delete the content of line, 8