[英]MS-Access: Querying data in an existing table
I'm trying to create a query in MS-Access that will lookup an exiting table and produce a particular result. 我正在尝试在MS-Access中创建一个查询,该查询将查找现有表并产生特定结果。 Here is an example of the existing table, let's call it tblA:
这是现有表的示例,我们称其为tblA:
C1 C2
1 Balloon
2 Tree
1 Bike
1 Tree
2 Balloon
2 Kite
1 Clown
1 Balloon
The query I'm trying to write will look at tblA, view column C2 and produce a result that will show values greater than 1. Here is my desired result of the query: 我尝试编写的查询将查看tblA,查看列C2并产生一个结果,该结果将显示大于1的值。这是我希望查询的结果:
C2
Balloon
Tree
Explanation of the expected output : What I'm trying to accomplish is if values in C1 share the same value in C2, I wan't the query to display the shared C2 value. 预期输出的说明 :我要完成的工作是,如果C1中的值在C2中共享相同的值,那么我将不查询以显示共享的C2值。 For example, C1 represents companies such as KFC and McDonalds.
例如,C1代表肯德基和麦当劳等公司。 C2 represents work dates.
C2代表工作日期。 If KFC and McDonalds share the same work date (eg Dec 1, 2017), I want the query to display only the work date, ie Dec 1, 2017.
如果肯德基和麦当劳共享相同的工作日期(例如,2017年12月1日),我希望查询仅显示工作日期,即2017年12月1日。
I'm a rookie at this stuff, so any help is greatly appreciated. 我是这个菜鸟的新手,因此非常感谢您的帮助。
Use the following: 使用以下内容:
SELECT Count(tblA.C1) AS CountOfC1, tblA.C2
FROM tblA
GROUP BY tblA.C2
HAVING (((Count(tblA.C1))>1));
You can try this : 您可以尝试以下方法:
select distinct A.C2 from tblA A
join tblA B on A.C2 = B.C2 and A.C1 <> B.C1
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