[英]Find all occurences by pattern and replace quotes within it in Python
I want to replace quotes "
with \\"
inside quotes in my long String. 我想在我的长字符串中用引号替换"
\\"
。 So, I came up with idea to find it by pattern and then replace those quotes. 因此,我想到了按模式找到它,然后替换那些引号的想法。 But what I'm missing is probably wrong pattern or wrong method usage: 但是我所缺少的可能是错误的模式或错误的方法用法:
string = re.sub(r"\"(.*)\"", r"\1", string).re.replace("\"", "\\\"")
Unfortunately it still replaces all quotes instead of those inside. 不幸的是,它仍然代替了所有引号而不是里面的引号。
This is what I want to achieve, replace this "text example.. something + "hello" + foo"
to this: "text example.. something + \\"hello\\" + foo"
这是我要实现的,将以下"text example.. something + "hello" + foo"
替换为: "text example.. something + \\"hello\\" + foo"
Note, that this can occur many times in my long string. 请注意,这可能在我的长字符串中多次发生。 Thanks for any kind of advice! 感谢您的任何建议! :) :)
@EDIT I think it is better to add the exact example of my string (my string looks similar to JSON
: @EDIT我认为最好添加我的字符串的确切示例(我的字符串看起来类似于JSON
:
"data": "fun () { return this.value * 20 + "x"; }"
now I want to remove quotes from x like this: 现在我想像这样从x删除引号:
"data": "fun () { return this.value * 20 + \\"x\\"; }"
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