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如何替换 Sendgrid 模板变量? (在 node-js 中)

[英]How to substitute Sendgrid template variables? (in node-js)

It seems to be a simple parameter I'm missing but I'm having trouble figuring out exactly what it is.这似乎是我遗漏的一个简单参数,但我无法弄清楚它到底是什么。

This is the request I'm sending with '@sendgrid/mail':这是我使用“@sendgrid/mail”发送的请求:

email.js:电子邮件.js:

const sgMail = require('@sendgrid/mail');

function emailRequest() {
    msg = {
      to: 'test+10@gmail.com
      from: 'info@owner.io',
      subject: 'Receipt for Business Expenses',
      template_id: 'db6d11ae-41e4-4e1a-a71b-f5368eb21c9c',
      personalizations: [
        {
          to: 'test+10@gmail.com,
          from: 'info@ownr.io,
          subject: 'Receipt for Business Expenses,
          template_id: 'db6d11ae-41e4-4e1a-a71b-f5368eb21c9c',
          substitutions: {
            ':firstname': 'Bobba',
            ':ordernumber': 'WHAAA',
            ':orderdate': 'today',
            ':ordertime': 'NOW!',
          },
          custom_args: {
            ':firstname': 'Bobba',
            ':ordernumber': 'WHAAA',
            ':orderdate': 'today',
            ':ordertime': 'NOW!',
          },
        },
      ],
      sub: {
        ':firstname': 'Bobba',
        ':ordernumber': 'WHAAA',
        ':orderdate': 'today',
        ':ordertime': 'NOW!',
      },
      substitutions: {
        ':firstname': 'Bobba',
        ':ordernumber': 'WHAAA',
        ':orderdate': 'today',
        ':ordertime': 'NOW!',
      },
    };

  sgMail.setApiKey(process.env.SENDGRID_API_KEY);

  return sgMail
    .send(msg)
    .then(response => {
      return response;
    })
    .catch(err => {
      throw err;
    });
}

The email sends, but I'm still getting unsubstituted templates:电子邮件已发送,但我仍然收到未替换的模板:

在此处输入图片说明

The source code for sendgrid-nodejs mail.js seems to say that as long as there is 'substitutions', it will initialize the mailing class with those substitutions but it's not working: sendgrid-nodejs mail.js 的源代码似乎说只要有“替换”,它就会用这些替换初始化邮件类,但它不起作用:

https://github.com/sendgrid/sendgrid-nodejs/blob/master/packages/helpers/classes/mail.js https://github.com/sendgrid/sendgrid-nodejs/blob/master/packages/helpers/classes/mail.js

https://sendgrid.com/docs/API_Reference/Web_API_v3/Mail/index.html https://sendgrid.com/docs/API_Reference/Web_API_v3/Mail/index.html

How do you properly substitute variables into templates?您如何正确地将变量替换为模板? Am I using the wrong package?我是否使用了错误的软件包?

After a bit more digging, I found the answer in the issues section of their github. 经过一番挖掘后,我在他们的github的问题部分找到了答案。 I was missing 'substitutionWrappers'. 我错过了'substitutionWrappers'。 To get it working, all I had to do was add 'substitutionWrappers' to the message along with 'substitutions': 为了使它工作,我所要做的就是在消息中添加'substitutionWrappers'以及'替换':

const msg = {
    to: 'test@email.com'
    from: 'info@gmail.io',
    subject: 'Receipt for Business Expenses',
    template_id: 'da6db3ae-41e4-4e1a-a71b-f5368ab41c9c',
    substitutionWrappers: [':', ''],
    substitutions: {
      firstname: 'Bobba',
      ordernumber: 'WHAAA',
      orderdate: 'today',
      ordertime: 'NOW!',
    },
  };

There's no need to specify the substitution wrappers as it will assume that you're using Handlebars templating by default.无需指定替换包装器,因为它会假定您默认使用 Handlebars 模板。

const sgMail = require('@sendgrid/mail');
sgMail.setApiKey(process.env.SENDGRID_API_KEY);
const msg = {
  to: 'recipient@example.org',
  from: 'sender@example.org',
  templateId: 'd-f43daeeaef504760851f727007e0b5d0',
  dynamicTemplateData: {
    subject: 'Testing Templates',
    name: 'Some One',
    city: 'Denver',
  },
};
sgMail.send(msg);

Check documentation to learn more 查看文档以了解更多信息

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