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将值更新为ruby中的哈希数组的有效方法?

[英]Efficient way to update values to array of hashes in ruby?

I have an array of hashes like below: 我有一系列的哈希,如下所示:

items = [ {"id" => 1, "cost" => '2.00'}, 
          {"id" => 2, "cost" => '6.00'}, 
          {"id" => 1, "cost" => '2.00'},
          {"id" => 1, "cost" => '2.00'}, 
          {"id" => 1, "cost" => '2.00'} ]

I would like to update the cost to '8.00' where the id = 1 . 我想将cost to '8.00'更新cost to '8.00' ,其中id = 1 I have tried with the each method like below which does work but I would like to know if there is another more efficient way of updating the values? 我已经尝试使用下面的each方法都可以正常工作,但是我想知道是否还有另一种更有效的更新值的方法?

items.each { |h| h["cost"] = "8.00" if h["id"] == 1 }

You could just use the same object: 您可以只使用同一对象:

item_1 = {'id' => 1, 'cost' => '2.00'}
item_2 = {'id' => 2, 'cost' => '6.00'}

items = [item_1, item_2, item_1, item_1, item_1]
#=> [{"id"=>1, "cost"=>"2.00"}, {"id"=>2, "cost"=>"6.00"},
#    {"id"=>1, "cost"=>"2.00"}, {"id"=>1, "cost"=>"2.00"},
#    {"id"=>1, "cost"=>"2.00"}]

This makes updates trivial: 这使得更新变得微不足道:

item_1['cost'] = '8.00'

items
#=> [{"id"=>1, "cost"=>"8.00"}, {"id"=>2, "cost"=>"6.00"},
#    {"id"=>1, "cost"=>"8.00"}, {"id"=>1, "cost"=>"8.00"},
#    {"id"=>1, "cost"=>"8.00"}]

You might consider changing your data structure from: 您可以考虑从以下位置更改数据结构:

items = [{"id" => 1, "cost" => '2.00'}, {"id" => 2, "cost" => '6.00'}, 
         {"id" => 1, "cost" => '2.00'}, {"id" => 1, "cost" => '2.00'}, 
         {"id" => 1, "cost" => '2.00'}]

To a hash like this: 像这样的哈希:

items = { 1 => '2.00', 2 => '6.00' }

To updating the record with id = 1 to 8.00 call: 要将id = 1的记录更新为8.00请调用:

items[1] = '8.00'

Or if you need to know the number of items, you might want to conside a structure like this: 或者,如果您需要知道项目数,则可能需要考虑如下结构:

items = { 1 => ['2.00', 4], 2 => ['6.00', 1] }

Than update like this: 比这样更新:

items[1][0] = '8.00'

You can achieve this by using each on array 您可以通过使用每个on数组来实现

items.each{|v| v["cost"] = "8.00" if v["id"] == 1 }

Cheers! 干杯!

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