斜边div颜色CSS JS

Question

i have 2 div like this

<div class="container">
    <div class="one"></div>
    <div class="two"></div>
</div>

CSS :

.container {
    width:100%;
}


.one , .two {
    width:50%;
    display:inline-block;
}

I want to give this 2 divs a diagonal side color to be like this

I tried rotate but it gave me some white spot.
Can any one help me please ?

Answer 1

A single gradient on the parent will do the visual:

 html { min-height:100%; background:linear-gradient(140deg, rgb(153, 180, 211)50%, rgb(217, 181, 150) 50%) } 

 example on HTML background sized at 100% viewport's height at the minimum. 

Answer 2

Try using an svg path css background property. See example below.

 .container { background: red; height: 117px; } .one { float: left; width: 50%; height: 117px; background: url("data:image/svg+xml;utf8,<svg xmlns='http://www.w3.org/2000/svg' width='100%' height='100%' viewBox='0 0 100 100' fill='blue' preserveAspectRatio='none'><path d='M0 0 L0 100 L50 100 L100 0 Z' /></svg>") no-repeat; } .two { float: left; width: 50%; height: 117px; } 

 <div class="container"> <div class="one"></div> <div class="two"></div> </div> 

Answer 3

You can use clip paths and 2 div within a container,

https://codepen.io/anon/pen/OOXPmv

HTML

<div id="wrapper">
  <div id="left"></div>
  <div id="right"></div>
</div>

CSS

body, html {
  margin: 0;
  padding: 0;
  height: 100%;
  width: 100%;
  background: #ccc;
}

#wrapper {
  width: 100%;
  height: 100%;
  background: #111;
}

#left {
  position: absolute;
  top: 0;
  left: 0;
  width: 101%; /* If you make it 100%, you get a bit of black showing along the diagonal */
  height: 100%;
  background: #99b4d3;
  -webkit-clip-path: polygon(0 0, 76% 0, 24% 100%, 0% 100%);
  clip-path: polygon(0 0, 76% 0, 24% 100%, 0% 100%);
}

#right {
  position: absolute;
  top: 0;
  right: 0;
  width: 100%;
  height: 100%;
  background: #d9b596;
  -webkit-clip-path: polygon(76% 0, 100% 0, 100% 100%, 24% 100%);
  clip-path: polygon(76% 0, 100% 0, 100% 100%, 24% 100%);
}