Python-查找特定的字符串[至少2个字]

Question

Another question from total Python newbie.

I have an array, user can input 5 different words/sentences, after user enters those 5, user enters one of the 5 texts again and program removes this string from array, than user adds another string and it appends directly to the Index = 0.

But the problem begins when i want to run over this array and find if any of the strings in the array have at least 2 words.

Text = []
for i in range(0, 5):
    Text.append(input('Enter the text: '))

    print (Text)
for i in range(0, 1):
    Text.remove(input('Enter one of the texts you entered before: '))
    print (Text)

for i in range(0, 1):
    Text.insert(0,input('Enter Some Text: '))
    print (Text)

for s in Text:
    if s.isspace():
        print(Text[s])

Output :

 Enter the text: A ['A'] Enter the text: B ['A', 'B'] Enter the text: CD ['A', 'B', 'C D'] Enter the text: E ['A', 'B', 'C D', 'E'] Enter the text: F ['A', 'B', 'C D', 'E', 'F'] Enter one of the texts you entered before: F ['A', 'B', 'C D', 'E'] Enter Some Text: G ['G', 'A', 'B', 'C D', 'E'] Press any key to continue . . . 

So, my code doesn't do anything, i need to somehow find if any of the strings have at least 2 words and print all of those words.

Answer 1

for s in Text:
if s.isspace():
    print(Text[s])

In the code above, s is the full string for example in your example s could be 'CD' and this string is not a space.

To check if s has two or more words you can use .split(' ') but before that you have to .strip() your string to delete spaces from borders.

s = 'Hello World '
print(s.strip().split(' '))
>>> ['Hello', 'World']

In the example above, s has two spaces, so strip delete the last space because is a border space and then split gives you a list of string that are separate by spaces.

So the solution to your problem could be

for s in Text:
    if len(s.strip().split(' ')) > 1:
        print(s.strip().split(' '))

Answer 2

So, my code doesn't do anything, i need to somehow find if any of the strings have at least 2 words and print all of those words.

Perhaps loop through the list and split each string. Then determine if the resulting sum is greater than 1:

text_list = ['G', 'A', 'B', 'C D', 'E']

for i in range(len(text_list)):
    if len(text_list[i].split(' ')) > 1:
        print(text_list[i])

Using list comprehension:

x = [w for w in text_list if len(w.split(' ')) > 1]
print(x)