[英]JavaScript/Node.JS - compact way of using OR operator?
Let's say I have a situation for checking a string. 假设我有一个检查字符串的情况。 I need to check if it matches
a
or matches b
. 我需要检查它是否匹配
a
或匹配b
。 Now, of course, I could just do 现在,我当然可以
var firstVar = "a"
var secondVar = "b"
var message = "atest" // note that I might not know what message is. it could be anything. it could be just "test" or just "a"
if ((message === firstVar + "test") || (message === secondVar + "test")) {
console.log("success!")
}
but is there any way to compact this down? 但是有什么办法可以压缩下来吗? Something relating to having a
myVar
being an array with values of a
and b
and then checking if message
starts with any value in myVar
? 与
myVar
是具有a
和b
值的数组然后检查message
是否以myVar
任何值开头有关的东西 ? If anyone has a tip, that would be much appreciated. 如果有人给小费,不胜感激。 Thanks!
谢谢!
Using an array with some
will be the simplest approach: 将数组与
some
将是最简单的方法:
var tests = ["a", "b"];
var message = "atest";
if (tests.some(function(t) { return message === t + "test"; })) {
console.log("success!")
}
If you can use ES6 and need to run this check very often, it might make sense to use 如果您可以使用ES6并且需要经常运行此检查,那么使用它可能很有意义
const choices = new Set(["a", "b"].map(t => t + "test"));
…
var message = "atest";
if (choices.has(message)) {
console.log("success!")
}
ES5: ES5:
var vars = ["a", "b"].map(function(v) { return v + "test"; }); var message = "atest"; if (vars.indexOf(message) > -1) { console.log("success!"); }
ES6: ES6:
var vars = ["a", "b"].map(v => v + "test"); var message = "atest"; if (vars.includes(message)) { console.log("success!"); }
I would probably use Array.prototype.some
on the array of prefixes and then...: 我可能会在前缀数组上使用
Array.prototype.some
然后...:
If the prefixes are all single characters, just do messsage[0] === prefix
, which should be the fastest option (no function calls and no string concatenation, just a simple and fast comparison operator. 如果前缀都是单个字符,则只需做
messsage[0] === prefix
,这应该是最快的选择(没有函数调用也没有字符串连接,只是一个简单而快速的比较运算符。
const prefixes = ["a", "b"]; const message1 = "atest"; const message2 = "btest"; const message3 = "ctest"; console.log(prefixes.some(prefix => message1[0] === prefix)); console.log(prefixes.some(prefix => message2[0] === prefix)); console.log(prefixes.some(prefix => message3[0] === prefix));
If the prefixes can have more than one character (also works for a single character), then I would do message.indexOf(prefix) === 0
: 如果前缀可以包含多个字符(也适用于单个字符),那么我将执行
message.indexOf(prefix) === 0
:
const prefixes = ["at", "bt"]; const message1 = "atest"; const message2 = "btest"; const message3 = "ctest"; console.log(prefixes.some(prefix => message1.indexOf(prefix) === 0)); console.log(prefixes.some(prefix => message2.indexOf(prefix) === 0)); console.log(prefixes.some(prefix => message3.indexOf(prefix) === 0));
You could also build and use a RegExp , which might be faster (depending on the amount and size of the prefixes) if you are going to execute the code multiple times (it will have a penalization the first time you build the RegExp from a string, but then you just reuse that one over and over): 您还可以构建和使用RegExp ,如果您打算多次执行代码,则速度可能更快(取决于前缀的数量和大小)(第一次从字符串构建RegExp时会受到惩罚) ,但是您可以反复使用该代码):
If the prefixes are a single character: 如果前缀是单个字符:
const prefixes = ["a", "b"]; const message1 = "atest"; const message2 = "btest"; const message3 = "ctest"; const regexp = new RegExp(`^[${ prefixes.join('') }]`); console.log(regexp.test(message1)) console.log(regexp.test(message2)) console.log(regexp.test(message3))
If the prefixes are multiple characters (also works for a single character): 如果前缀是多个字符(也适用于单个字符):
const prefixes = ["at", "bt"]; const message1 = "atest"; const message2 = "btest"; const message3 = "ctest"; const regexp = new RegExp(`^(${ prefixes.join('|') })`); console.log(regexp.test(message1)) console.log(regexp.test(message2)) console.log(regexp.test(message3))
If you want to check that message
is actually a combination of any of those prefixes plus something else, let's say "test"
in your example, then you may want to precompute all the possible options: 如果要检查
message
是否实际上是这些前缀中的任何一个加上其他内容的组合,在示例中说"test"
,则可能需要预先计算所有可能的选项:
With an Array (or Set as @Bergi suggested) and Array.prototype.includes
or Array.prototype.indexOf
使用Array(或建议设置为@Bergi)和
Array.prototype.includes
或Array.prototype.indexOf
const prefixes = ["a", "b"]; const word = "test"; const options = prefixes.map(prefix => `${ prefix }${ word }`); const message1 = "atest"; const message2 = "btest"; const message3 = "ctest"; console.log(options.includes(message1)); console.log(options.includes(message2)); console.log(options.includes(message3)); console.log(options.indexOf(message1) !== -1); console.log(options.indexOf(message2) !== -1); console.log(options.indexOf(message3) !== -1);
With a RegExp and RegExp.prototype.test
or String.prototype.match
: 使用RegExp和
RegExp.prototype.test
或String.prototype.match
:
const prefixes = ["a", "b"]; const word = "test"; const regexp = new RegExp(`^(${ prefixes.join("|") })${ word }`); const message1 = "atest"; const message2 = "btest"; const message3 = "ctest"; console.log(regexp.test(message1)); console.log(regexp.test(message2)); console.log(regexp.test(message3)); console.log(!!message1.match(regexp)); console.log(!!message2.match(regexp)); console.log(!!message3.match(regexp));
Use includes
; 用途
includes
; based on your edit: 根据您的修改:
const allowed = ['a','b','ccc'];
if( allowed.includes(`${ message }test`) ) {
console.log("success!")
}
Example of using includes and vanilla 使用include和vanilla的示例
ES6 way ES6方式
const testArray = [1,2,3];
testArray.includes(1); //returns true
testArray.includes(24); //returns false
ES5 way ES5方式
var testArray = [1,2,3];
testArray.indexOf(1) // returns 1 since its a member.
testArray.indexOf(43) //returns -1 since it's not a member.
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