使用JavaScript在动态创建的单选按钮上显示动态创建的文本框

Question

I am receiving some data via json and based on the inputs I have dynamically created a table that displays pre-selected radio buttons (Green / Yellow / Red) based on the values in the input. In the third column, I am displaying a comments box.

Now, I only want to display the comment box only if yellow / red radio button comes as input or if I select.

Here is my code in use:

 $(document).ready(function() { var appStatus = [{ "category": "Overall Status", "status": "0" }, { "category": "System Availability", "status": "1" }, { "category": "Whatever", "status": "2" }]; var tr; for (var i = 0; i < appStatus.length; i++) { tr = $('<tr/>'); tr.append("<td>" + appStatus[i].category + "</td>"); tr.append('<tr id="row' + i + '"><td><input type="radio" name="inlineRadioOptions_' + i + '[]" value="0" id="inlineRadio0"' + (appStatus[i].status == '0' ? ' checked="checked"' : '') + '><font color="black">Grey &emsp;</font><label class="radio-inline"><input type="radio" name="inlineRadioOptions_' + i + '[]" value="1" id="inlineRadio1"' + (appStatus[i].status == '1' ? ' checked="checked"' : '') + '><font color="green">Green &emsp;</font><label class="radio-inline"><input type="radio" name="inlineRadioOptions_' + i + '[]" id="inlineRadio2" value="2"' + (appStatus[i].status == '2' ? ' checked="checked"' : '') + '><font color="yellow">Yellow &emsp;</font></label><label class="radio-inline"><input type="radio" name="inlineRadioOptions_' + i + '[]" id="inlineRadio3" value="3"' + (appStatus[i].status == '3' ? ' checked="checked"' : '') + '> <font color="red">Red</font></label><td></tr>'); //tr.append("<td>" + "<input>" + appStatus[i].comments + "</input>" + "</td>"); tr.append("<td>" + '<tr id="row' + i + '"><td><input type="text" id="appStatus[i].comments" name="appStatus[i].comments" placeholder="Comments" class="form-control name_list" required' + "</td>"); $('table').append(tr); } $('#result').on('click', function() { var new_status = []; $('.table tbody tr').each(function() { new_status.push({ category: $(this).find('td:eq(0)').text(), status: $(this).find(':radio:checked').val() }); }); console.log(new_status); }); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <table class="table table-hover"> <thead> <th>Category</th> <th>Status</th> <th>Comments</th> </thead> </table> 

Answer 1

Add handlers to each radio input. Since you are using jQuery, the attached event handlers have this as the event source. You must separate your longer <tr>...</tr> blocks in order to achieve this.

A simple example:

table.append('<tr/>').append(
    $('<td>').append(
        $('<input type="radio" name="x">').change(function () {
            $(this).closest('td').find('input.comments').toggle(true or false);
        })
    )
)

...but you can be smarter and write this much clearer using variables.

There's also that you are appending <tr> elements inside another in your code, which leads to invalid HTML. Plus some other small glitches that need to be worked on.