具有无限参数的类方法

Question

I have the following code:

$array = array('foo', 'foo', 'bar', 'bis', 'ter')
Arrays::without($array, 'foo', 'bis') // Returns array('bar', 'ter')

As you can see, the second and third parameter to calling the Arrays::without function. you can pass as many parameters as you want, such as:

Arrays::without($array, 'foo', 'bis','athirdparam','afourthparam') // Returns array('bar', 'ter')

Im trying to encapsulate this into a static method inside a class i have:

public static function without($arr,$p)
{
    return Arrays::without($arr,$p);
}

What i need to know is if there is a way i can pass unlimited arguments to this method without and use them inside my funciton call to Arrays::without

Answer 1

You can call:

Arrays::without($arr, ...$p);

Where $p is an array or write your method like that:

public static function without($arr,$p)
{
    return Arrays::without($arr, ...$p);
}

But it's quite unnecessary.

Check splat operator: http://php.net/manual/en/migration56.new-features.php#migration56.new-features.splat

Answer 2

在函数内部使用func_get_args（） ，或者在public static function without(...$args)中使用函数签名...。所有这些都在PHP Docs中进行了描述。