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在多处加入一对多

[英]Join one to many with multiple where

This is products table: 这是产品表:

+-----------+
| id | name |
+-----------+
| 1  | A    | 
+-----------+
| 2  | B    | 
+-----------+
| 3  | C    | 
+-----------+ 

This is product_filter table: 这是product_filter表:

+-----------------+-----------+
| id | product_id | filter_id |
+-----------------+-----------+
| 1  | 1          | 1         |
+-----------------------------+
| 2  | 1          | 2         |
+-----------------------------+ 
| 3  | 2          | 1         |
+-----------------------------+
| 4  | 2          | 2         |
+-----------------------------+
| 5  | 2          | 3         |
+-----------------------------+
| 6  | 3          | 1         |
+-----------------------------+
| 7  | 3          | 3         |
+-----------------------------+

i want if where product_filter.filter_id = 1 and product_filter.filter_id = 2 the result of product.id is 1 and 2 我想如果product_filter.filter_id = 1和product_filter.filter_id = 2的地方product.id的结果是1和2

if where product_filter.filter_id = 1 and product_filter.filter_id = 3 the result of product.id is 1 and 3 如果product_filter.filter_id = 1且product_filter.filter_id = 3,则product.id的结果为1和3

This is my query, and it's not works: 这是我的查询,它不起作用:

SELECT `products`.`id`, `product_filter`.`filter_id`
FROM `products` 
JOIN `product_filter` ON `product_filter`.`product_id` = `products`.`id` 
WHERE `product_filter`.`filter_id` = '1' AND `product_filter`.`filter_id` = '2'

Instead of AND use IN : 代替AND使用IN

SELECT
    p.id,
    pf.filter_id
FROM products p
INNER JOIN product_filter pf
    ON pf.product_id = p.id
WHERE
    pf.filter_id IN (1, 2);

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