在一行mysql中为一个用户选择所有行

Question

I have a mysql table which has the below structure

id,username,attribute,value,realname,birthdate,phone 

and I have these records in the table

1,john,Cleartext-Password,ss,johnsmith,1/1/1990,9786865754
2,john,Expiration,20/1/2018,null,null,null

I want to write a query that shows the below result

username|password|expir     |realname|birthdate|phone 
john    |ss      |20/1/2018 |johnsmith|1/1/1990|9786865754

I tried using the query mentioned below. But I don't seem to get the desired result.

select c1.username ,c1.value as 'password',c1.adsoyad,c1.telefon,c1.email,c1.dtarih,c1.tcno,c2.value as 'expired' from radcheck c1 INNER join radcheck c2 on c1.username=c2.username and c1.attribute='Cleartext-Password' and c2.attribute='Expiration' and c1.username='john' and c2.username='john'

Answer 1

Does conditional aggregation do what you want?

select c.username,
       max(case when c.attribute = 'password' then c.value end) as password,
       max(case when c.attribute = 'expiration' then c.value end) as expiration,
       max(c.realname) as realname, min(c.birthdate) as birthdate, max(c.phone) as phone
from radcheck c
group by username