[英]Awaiting asynchronous actions
I've got a static generic method that is intended to perform an action on a collection in parallel (don't worry about throttling; I've got that covered; code here is the dumbed-down version): 我有一个静态通用方法,旨在并行地对一个集合执行操作(不用担心节流;我已经覆盖了;这里的代码是精简版):
public static IEnumerable<Task> RunAllAsync<T>(this IEnumerable<T> enumerable, Action<T> action)
{
var tasks = new List<Task>();
foreach (var t in enumerable)
{
tasks.Add(Task.Run(() => action(t)));
}
return tasks;
}
Here's an example of how the usage might be: 这是用法示例:
public async Task UsageSync()
{
var numbers = Enumerable.Range(1, 5);
var random = new Random();
var tasks = numbers.RunAllAsync(i =>
{
Console.WriteLine($"A {i}");
Thread.Sleep(random.Next(1000));
Console.WriteLine($"B {i}");
});
Console.WriteLine("Awaiting end");
await Task.WhenAll(tasks.ToArray());
Console.WriteLine("awaited");
Thread.Sleep(2000);
Console.WriteLine("Finished");
}
Output: 输出:
Awaiting end
A 4
A 5
A 1
A 2
A 3
B 3
B 2
B 1
B 5
B 4
awaited
Finished
All as expected. 一切都如预期。 But now we make that action itself an async delegate:
但是现在我们使该动作本身成为异步委托:
public async Task UsageAsync()
{
var numbers = Enumerable.Range(1, 5);
var random = new Random();
var tasks = numbers.RunAllAsync(async i =>
{
Console.WriteLine($"A {i}");
await Task.Run(() =>
{
Console.WriteLine($"B {i}");
Thread.Sleep(random.Next(1000));
Console.WriteLine($"C {i}");
});
});
Console.WriteLine("Awaiting end");
await Task.WhenAll(tasks.ToArray());
Console.WriteLine("awaited");
Thread.Sleep(2000);
Console.WriteLine("Finished");
}
Output: 输出:
Awaiting end
A 4
B 4
A 1
A 5
A 3
A 2
B 2
awaited
B 5
B 1
B 3
C 3
C 2
C 1
C 5
C 4
Finished
See that? 看到了吗? The method reached "awaited" before the threads finished!
在线程完成之前,该方法已“等待”!
What should I be doing to ensure that the asynchronous action is awaited? 我应该怎么做才能确保等待异步操作?
Since you're dealing with an Action<T>
, async i => { ... }
gets translated into an async void
method. 由于您正在处理
Action<T>
,因此async i => { ... }
被转换为async void
方法。 async void
by design makes it impossible to wait for it to finish. 设计上的
async void
使其无法等待完成。 Change your parameter to Func<T, Task> func
and changing the call action(t)
to await func(t)
. 将您的参数更改为
Func<T, Task> func
并将调用action(t)
更改为await func(t)
。
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