[英]REGEXP_REPLACE query oracle
I have a text like following. 我有一个类似下面的文字。
( ( tt.TRAN_TYPE IN
( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1332 )
AND tt.CONTRACT IN
( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1333 )
AND tt.CUSTOMER_STATE NOT IN
( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1334)
AND tt.COT_IND IN
( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1335 ))
OR ( tt.TRAN_TYPE IN
( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1336 )
AND tt.WHLSE_COT NOT IN
( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1337 )
AND tt.COT_IND IN
( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1338 )) )
I need to replace tt.* with condition tt.* IS NOT NULL and tt.*... as below. 我需要用条件tt。* IS NOT NULL和tt。* ...替换tt。*,如下所示。
(
( (tt.TRAN_TYPE IS NOT NULL AND tt.TRAN_TYPE IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1332 ))
AND (tt.CONTRACT IS NOT NULL AND tt.CONTRACT IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1333))
AND (tt.CUSTOMER_STATE IS NOT NULL AND tt.CUSTOMER_STATE NOT IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1334))
AND (tt.COT_IND IS NOT NULL AND tt.COT_IND IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1335)))
OR ( (tt.TRAN_TYPE IS NOT NULL AND tt.TRAN_TYPE IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1336))
AND (tt.WHLSE_COT IS NOT NULL AND tt.WHLSE_COT NOT IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1337))
AND (tt.COT_IND IS NOT NULL AND tt.COT_IND IN ( SELECT RULE_VALUE FROM GP_RULE_VALUE WHERE RULE_ID=1338)))
)
Please provide REGEXP_REPLACE or Any other trick if available in ORACLE. 请提供REGEXP_REPLACE或任何其他技巧(如果ORACLE中可用)。
NOTE : To me main challenge seems to be replace such a way that query order remains proper (ie opening and closing brackets placing properly) 注意:对我来说,主要的挑战似乎是以使查询顺序保持正确的方式进行替换(即,将右括号和右括号放置正确)
Try this. 尝试这个。
SELECT REGEXP_REPLACE (yourtext, 'tt\.(.+) ', 'tt.\1 IS NOT NULL AND tt.\1 ')
FROM yourtable;
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