如何遍历字典中每个键具有多个值的值

Question

I have a dictionary like this:

{4722: "['children', 'dance', 'education','technology', 'teaching']",
3200: "['alternative energy', 'sustainability', 'technology']",
1636: "['computers', 'performance', 'simplicity', 'software', 'ice']",
1697: "['MacArthur grant', 'inequality', 'technology', 'pollution']"}

Now I want to find the word 'technology' in each row and sum the keys. Like here I should have the sum of 4722 + 3200 + 1697 .

Can anyone help me please?

I should mention that my original data frame has 2000 rows.

Answer 1

Use the sum() built-in function, passing an appropriate generator expression: sum(k for k,v in d.items() if 'technology' in v) (nb use d.iteritems() in Python2).

Runnable demo:

d = {
    4722: "['children', 'dance', 'education','technology', 'teaching']",
    3200: "['alternative energy', 'sustainability', 'technology']",
    1636: "['computers', 'performance', 'simplicity', 'software', 'ice']",
    1697: "['MacArthur grant', 'inequality', 'technology', 'pollution']"
}

result = sum(k for k,v in d.items() if 'technology' in v)
assert result == 9619

References:

• https://docs.python.org/2/library/functions.html#sum
• https://docs.python.org/2/library/stdtypes.html#dict.items
• https://docs.python.org/2/reference/expressions.html#grammar-token-generator_expression

Answer 2

your_data = {
    4722: "['children', 'dance', 'education','technology', 'teaching']",
    3200: "['alternative energy', 'sustainability', 'technology']",
    1636: "['computers', 'performance', 'simplicity', 'software', 'ice']",
    1697: "['MacArthur grant', 'inequality', 'technology', 'pollution']"
}

sum_up = 0
for k, v in your_data.items():
    if 'technology' in v:
        sum_up += k

print('sum_up:', sum_up)