具有最大日期实例的SQL查询

Question

Given the following table:

DATE      |ARRANGMENT_STATUS | CUSTOMER
----------+------------------+-------
2017-01-01|BROKEN            |0001
2017-02-01|OK                |0001
2017-03-01|BROKEN            |0001

How can I query the DB so result will give me the latest broken status( 2017-03-01) - I dont want to get broken status if they are not the latest ( 2017-01-01)

Hope it makes sence, thanks

Answer 1

If you want all information in the row, you can use order by and limit :

select t.*
from t
where t.arrangement_status = 'Broken'
order by t.date desc
limit 1;

If you only want the date, the JNevill's solution is fine.

Answer 2

获取该状态的max（date）：

SELECT max(date) FROM table WHERE arrangement_status = 'Broken'