[英]Check if selection contains link
I am creating a rich text editor and I would like to use the same button to link and unlink selections.我正在创建一个富文本编辑器,我想使用相同的按钮来链接和取消链接选择。
document.execCommand('createLink'...)
and document.execCommand('unlink'...)
allow users to link and unlink window.getSelection().toString()
. document.execCommand('createLink'...)
和document.execCommand('unlink'...)
允许用户链接和取消链接window.getSelection().toString()
。
However, there are no inbuilt methods to determine whether a selection is linked or not in the first place, so my question is: How can you check whether or not a selection is linked?但是,首先没有内置方法来确定选择是否链接,所以我的问题是:如何检查选择是否链接?
I have tried using document.queryCommandState('createLink')
and document.queryCommandState('unlink')
, but both queries always return false
, even though, for example, document.queryCommandState('bold')
works properly.我曾尝试使用
document.queryCommandState('createLink')
和document.queryCommandState('unlink')
,但两个查询总是返回false
,即使,例如, document.queryCommandState('bold')
工作正常。
I found the following piece of code, which works well enough for the time being, kicking around on SO:我发现了以下代码,它暂时运行良好,在 SO 上运行:
const isLink = () => {
if (window.getSelection().toString !== '') {
const selection = window.getSelection().getRangeAt(0)
if (selection) {
if (selection.startContainer.parentNode.tagName === 'A'
|| selection.endContainer.parentNode.tagName === 'A') {
return [true, selection]
} else { return false }
} else { return false }
}
}
You also may be able to retrieve the link HTML element and pass it to Selection.containsNode()您还可以检索链接 HTML 元素并将其传递给Selection.containsNode()
const linkHtmlElement = document.getElementById('yourId');
// should return true if your linkHtmlElement is selected
window.getSelection().containsNode(linkHtmlElement)
You need to check the anchorNode
and focusNode
text nodes to see if they are a
elements.您需要检查
anchorNode
和focusNode
文本节点以查看它们是否a
元素。 More details on MDN有关MDN 的更多详细信息
function isLink () { const selection = window.getSelection() const startA = selection.anchorNode.parentNode.tagName === 'A' const endA = selection.focusNode.parentNode.tagName === 'A' return startA || endA }
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.