不区分大小写的字典值匹配

Question

Re .lower usage (?), how can I make case-insensitive matching for dictionary values? For example, config[camID]["media_file"]] should match both, lowercase and uppercase extensions, even though the dictionary has lowercase only.

1 line from dictionary:

config['d5']['media_file'] = ('nef', 'jpg', 'avi')

Code:

for f in files:
     if any([f.endswith(x) for x in config[camID]["media_file"]]):
         os.rename(os.path.join(path, f), 
                   os.path.join(path, "%s%s%s" % (config[camID]['cam_name'], "_", f)))

(If there is an "in-dictionary" solution (ie, instead in the code), that would be also interesting to know.)

Answer 1

You need to convert the data to a standard before stores in the dict (like lower). After storage there is no way to search for case insensitive inside dict ou set, because this search are made by hash.