在Unix中排序唯一列
[英]Sort Unique column in Unix
问题描述
I have been looking for an answer for a good amount of time but it seems that it hasn't been answered yet. 
我一直在寻找答案很长时间，但似乎尚未找到答案。 I do apologize if this question has already been answered. 如果这个问题已经回答，我深表歉意。
So i am trying to sort the number of appearances from each ID from High to Low. 所以我正在尝试从高到低从每个ID排序出现次数。
From the following command: sort -k1,1 File.txt | uniq -c 从以下命令： sort -k1,1 File.txt | uniq -c sort -k1,1 File.txt | uniq -c I get this result : sort -k1,1 File.txt | uniq -c我得到以下结果：
1 21423
3 21447
5 21448
3 21513
1 21584
1 21585
1 21586
The result I want: 我想要的结果：
5 21448
3 21447
3 21513
1 21423
1 21584
1 21585
1 21586
It does sort the second column even though I typed -k1,1 I have tried different parameters and options such as -n . 即使我键入了-k1,1它也会对第二列进行排序，尽管我尝试了其他参数和选项，例如-n 。 Any leads would help me a lot. 任何线索都将对我有很大帮助。 Thanks in advance! 提前致谢！
1 个解决方案
解决方案1
0 已采纳 2017-11-12 20:29:15
You need to sort the output of uniq -c : 您需要对uniq -c的输出进行排序：
... | uniq -c | sort -nr
When you want to sort lines by the count, it doesn't matter how the items were sorted before calling uniq -c , because the counts will only be known after the call to uniq -c . 如果要按计数对行进行排序，则在调用uniq -c之前如何对项目进行排序并不重要，因为仅在调用uniq -c之后才能知道计数。
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