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Promise.reject出现TypeScript错误

[英]TypeScript error with Promise.reject

Why do I receive the following compilation error with this TypeScript method which I wrote: 为什么我用编写的此TypeScript方法收到以下编译错误:

getFile(path: string): Promise<FileEntry> {
  return this.file.resolveLocalFilesystemUrl(path)
    .then(entry => {
      if (entry.isFile) {
        return <FileEntry>entry;
      } else {
        let err = new FileError(13);         
        err.message = 'input is not a file';
        return Promise.reject(err);
      }
    });
}

I get the error: 我得到错误:

Argument of type '(entry: Entry) => Promise<never> | FileEntry' is not assignable to parameter of type '(value: Entry) => PromiseLike<never>'. Type 'Promise<never> | FileEntry' is not assignable to type 'PromiseLike<never>'. Type 'FileEntry' is not assignable to type 'PromiseLike<never>'. Property 'then' is  missing in type 'FileEntry'.

The definition for resolveLocalFilesystemUrl is as follows: resolveLocalFilesystemUrl的定义如下:

resolveLocalFilesystemUrl(fileUrl: string): Promise<Entry>;

FileEntry is a subclass of Entry , hence the casted return. FileEntryEntry的子类,因此是强制返回。 However, the error is around Promise.reject . 但是,该错误与Promise.reject

If I change my reject line to the following, it works: 如果我将拒绝行更改为以下内容,它将起作用:

return Promise.reject<FileEntry>(err);

Do I need to return Promise.reject(...) and what is the correct implementation? 我是否需要返回Promise.reject(...) ,正确的实现是什么?

To return a promise you create a new Instance of a promise and return this instance. 要返回承诺,您可以创建一个承诺的新实例并返回该实例。 The constructor takes a function that receives the resolve and reject callbacks you should call, when your logic succeeds or fails. 构造函数采用一个函数,该函数接收逻辑成功或失败时应调用的resolve和拒绝回调。

To let your promise "return" your result, you don't write return result , but call resolve(result) . 为了让您的承诺“返回”结果,您不编写return result ,而是调用resolve(result)

getFile(path: string): Promise<FileEntry> {
  return new Promise<FileEntry>((resolve, reject) => {
    // Your logic here.
    // call resolve() on success
    // or reject() on failure
  });
}

So in your case it should look like the following: 因此,在您的情况下,它应如下所示:

getFile(path: string): Promise<FileEntry> {
  return new Promise<FileEntry>((resolve, reject) => {
    this.file.resolveLocalFilesystemUrl(path)
    .then(entry => {
      if (entry.isFile) {
        resolve(<FileEntry>entry); // Success
      } else {
        let err = new FileError(13);         
        err.message = 'input is not a file';
        reject(err); // Error
      }
    });
  });
}

If you want to learn more about promises read for example here: https://developers.google.com/web/fundamentals/primers/promises 如果您想了解有关承诺的更多信息,请阅读以下示例: https : //developers.google.com/web/fundamentals/primers/promises

You shouldn't really return a resolved or rejected promise inside of your promise chain. 您不应该真正在承诺链中返回已解决或被拒绝的承诺。

When you want to indicate an error you should just throw an error: 当您想指出一个错误时,您应该抛出一个错误:

else
   let err = new FileError(13);         
   err.message = 'input is not a file';
   throw err;

You can try wrapping the return entry with a Promise.resolve. 您可以尝试使用Promise.resolve包装return entry This solved when I had a similar error. 当我遇到类似错误时,此问题解决了。

getFile(path: string): Promise<FileEntry> {
  return this.file.resolveLocalFilesystemUrl(path)
    .then(entry => {
      if (entry.isFile) {
        // See this
        return Promise.resolve(<FileEntry>entry);
      } else {
        let err = new FileError(13);         
        err.message = 'input is not a file';
        return Promise.reject(err);
      }
    });
}

You won't have to write the verbose new Promise((resolve, reject) => {}) because your underlying this.file.resolveLocalFilesystemUrl already returns a Promise and you can chain on it. 您不必编写冗长的new Promise((resolve, reject) => {})因为您的基础this.file.resolveLocalFilesystemUrl已经返回了Promise,您可以在其上进行链接。 (Which I feel is the correct way.) (我认为这是正确的方法。)

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