数字1 - 1000的素数测试

Question

As a homework I have to write a prime number test, that gives back a "true" or "false" statement. The tricky thing is, I have to write a csv.-file that includes the "true" and "false" statements for the numbers 1 to 1000. I used this code for the prime number test

def Primzahl(n):
if n < 2:
    return False
if n == 2: 
    return True    
if not n & 1: 
    return False
for x in range(3, int(n**0.5) + 1, 2):
    if n % x == 0:
        return False
return True

and

for i in range (1,1001):
    Primzahl (i)
    print (i)

My for-loop only gives out the numbers 1,1000 but not the true or false statements. Do I have to include if and else in my for loop? Can anyone help?

Answer 1

The problem is print(i) . That will write i , which is the number from your range call. You will also need to print the value returned by your function, eg print(Primzahl(i)) .

Answer 2

Currently you're only printing i, and not the return value from your method. You aren't doing anything with the return value from your method. You should assign the result to a variable and print the variable also. (You could also just call the method from within the print statement.)

for i in range (1,1001):
isPrime = Primzahl(i)
print (i + ": " + isPrime)